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IRISSAK [1]
4 years ago
8

Ammonia is produced commercially by the Haber reaction: N2(8)+ 3H2(8)

Chemistry
1 answer:
Shalnov [3]4 years ago
5 0

This is an incomplete question, here is a complete question.

Ammonia is produced commercially by the Haber  reaction:

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)+Heat

The formation of ammonia is favored by

A) an increase in pressure

B) a decrease in pressure

C) removal of N₂(g)

D) removal of H₂(g)

Answer : The correct option is, (A) an increase in pressure.

Explanation :

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

Le-Chatelier's principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

Increase the pressure :

If the pressure in the equilibrium is increased, the equilibrium will shift in the direction where fewer total molecules are shown in the balanced chemical equation.

In the given reaction, there are 4 molecules present on reactant side and 2 molecules on product side. That means, less molecules present on product side. Thus, the reaction will shift in right direction that is towards the product.

Removal the reactant molecule :

If any of reactant molecule in the equilibrium is removed, then the equilibrium will shift in left direction that is towards the reactant.

Hnece, the formation of ammonia is favored by  an increase in pressure.

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Answer:

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Explanation:

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4 0
3 years ago
Hydrogen fuel cells that operate at lower temperatures use more expensive platinum electrode catalysts.
mote1985 [20]
The correct answer is B) they operate at a higher efficiency. sorry hope the answers not to late :(
5 0
4 years ago
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why is there a dip in ionization energies between the elements Be and B, between Mg and Al, and between Ca and Ga?
expeople1 [14]
Be and B: Be is 1s2 2s2 and B is 1s2 2s2 2p1
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5 0
3 years ago
Quinine (C20H24N2O2) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine
dolphi86 [110]

Answer:

The pH of saturated solution of the quinine is 10.05

Explanation:

Quinine (Q) is C20H24N2O2 has a molar mass of 324.4 g/mol

Q can behave as a weak base. Kb and pKb can be calculated for weak bases

pKb1 is to be considered when solving the question.

pKb1 = 5.1

Step 1 : Calculate the Kb of Quinine

            pKb1 = - log [kb]

                5.1  = - log [kb]

                take Antilog of both side

             [kb] = 7.94 x 10∧-6

Step 2: Calculate the concentration of saturated solution of Q in mol/dm3

           From the question, 1900 ml of solution contains 1 g of Q

           Therefore,  1000 ml of solution will contain........... x g of Q

           x = 1000 /1900

           x = 0.526 g in 1 dm3

In calculating concentration in mol/dm3,

Concentration in mol/dm3 = concentration in g /dm3 divided by molar mass

Molar mass of Q = 324.4

Concentration in mol/dm = 0.526 /324.4

                                         = 0.0016 mol/dm3

Step 3: Calculating the Concentration of OH-

            At Equilibrium, Kb = x² / 0.0016

            7.94 x 10∧-6 = x² / 0.0016

            x = √ 0.0016 × 7.94 x 10∧-6

            x = 1. 127 × 10∧-4 mol/dm3

The concentration of OH- = 1. 127 × 10∧-4 mol/dm

Step 4:  Calculating the pH of Quinine

           Recall, pOH = - log [OH-]

           pOH = - log [1. 127 × 10∧-4]

           pOH = 3.948

           Also recall that pH + pOH = 14

           pH = 14 - 3.948

           pH = 10.05

           

8 0
4 years ago
2. Calculate the concentration (in molarity) of a NaOH solution if 25.0 mL of the solution are needed to neutralize 17.4 mL of a
zimovet [89]

Answer:

0.217 M NaOH

Explanation:

M1V1 = M2V2

M1 = 0.312 M HCl

V1 = 17.4 mL HCl

M2 = ?

V2 = 25.0 mL NaOH

Solve for M2 --> M2 = M1V1/V2

M2 = (0.312 M)(17.4 mL) / (25.0 mL) = 0.217 M NaOH

3 0
3 years ago
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