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Angelina_Jolie [31]
3 years ago
12

Which is the first element in the periodic table to have an electron configuration in the 4th energy level? beryllium carbon pot

assium titanium
Chemistry
2 answers:
asambeis [7]3 years ago
8 0

Answer:

The answer is: Potassium because is the first element in period four.

Explanation:

Ok, the electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals.  Since 1s can only hold two electrons, the next 2 electrons are in the 2s orbital. Then put six in the 2p orbital and put the next two electrons in the 3s. Now, move to the 3p where it is place the next six electrons. Then  shift to the 4s orbital where we place the remaining one electron. Therefore the Potassium electron configuration will be:

1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{1}

Nimfa-mama [501]3 years ago
5 0

titanium electronic configuration

3d2 4S2

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rutherford's experiment indicated that matter was not as uniform as it appears what part of his experimental results implied thi
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2 years ago
at standard pressure, what is the temperature at which a saturated solution of NH4Cl has a concentration of 60g NH4CL/100 g H2O
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A solution prepared by dissolving 0.100 mole of propionic acid in enough water to make 1.00 L of solution is observed to have a
torisob [31]

Answer:

C) k_a=1.3\times 10^{-5}

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pH = - log [H⁺]

The expression of the pH of the calculation of weak acid is:-

pH=-log(\sqrt{k_a\times C})

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4 0
3 years ago
What is the percent by mass of carbon in C10 H14 N2?
MrMuchimi
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8 0
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DanielleElmas [232]

<u>Answer:</u> The amount of heat absorbed by the solution is 2.795 kJ

<u>Explanation:</u>

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\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

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Volume of water = [70 + 70] = 140 mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{140mL}\\\\\text{Mass of water}=(1g/mL\times 140mL)=140g

To calculate the heat absorbed, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

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c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(28.74-23.97)^oC=4.77^oC

Putting values in above equation, we get:

q=140g\times 4.186J/g^oC\times 4.77^oC=2795.4J=2.795kJ

Hence, the amount of heat absorbed by the solution is 2.795 kJ

3 0
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