Answer:
8608.18 balloons
Explanation:
Hello! Let's solve this!
Data needed:
Enthalpy of propane formation: 103.85kJ / mol
Specific heat capacity of air: 1.009J · g ° C
Density of air at 100 ° C: 0.946kg / m3
Density of propane at 100 ° C: 1.440kg / m3
First we will calculate the propane heat (C3H8)
3000g * (1mol / 44g) * (103.85kJ / mol) * (1000J / 1kJ) = 7.08068 * 10 ^ 6 J
Then we can calculate the mass of the air with the heat formula
Q = mc delta T
m = Q / c delta T = (7.08068 * 10 ^ 6 J) / (1.009J / kg ° C * (100-25) ° C) =
m = 93566.96kg
We now calculate the volume of a balloon.
V = 4/3 * pi * r ^ 3 = 4/3 * 3.14 * 1.4m ^ 3 = 11.49m ^ 3
Now we calculate the mass of the balloon
mg = 0.946kg / m3 * 11.49m ^ 3 = 10.87kg
The amount of balloons is
93566.96kg / 10.87kg = 8608.18 balloons
Answer:
7,94 minutes
Explanation:
If the descomposition of HBr(gr) into elemental species have a rate constant, then this reaction belongs to a zero-order reaction kinetics, where the r<em>eaction rate does not depend on the concentration of the reactants. </em>
For the zero-order reactions, concentration-time equation can be written as follows:
[A] = - Kt + [Ao]
where:
- [A]: concentration of the reactant A at the <em>t </em>time,
- [A]o: initial concentration of the reactant A,
- K: rate constant,
- t: elapsed time of the reaction
<u>To solve the problem, we just replace our data in the concentration-time equation, and we clear the value of t.</u>
Data:
K = 4.2 ×10−3atm/s,
[A]o=[HBr]o= 2 atm,
[A]=[HBr]=0 atm (all HBr(g) is gone)
<em>We clear the incognita :</em>
[A] = - Kt + [Ao]............. Kt = [Ao] - [A]
t = ([Ao] - [A])/K
<em>We replace the numerical values:</em>
t = (2 atm - 0 atm)/4.2 ×10−3atm/s = 476,19 s = 7,94 minutes
So, we need 7,94 minutes to achieve complete conversion into elements ([HBr]=0).
Answer: 2.34 L
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 0.850 atm
= final pressure of gas = 1.50 atm
= initial volume of gas = 4.25 L
= final volume of gas = ?
= initial temperature of gas = 
= final temperature of gas = 
Now put all the given values in the above equation, we get:
Thus the final volume will be 2.34 L
Answer:
B. Inside the cell, but outside the nucleus
Explanation:
it's in cytoplasm which surrounds the nucleus..... i guess
