-x^2+2x+3=x^2-2x+3 add x^2 to both sides
2x+3=2x^2-2x+3 subtract 2x from both sides
3=2x^2-4x+3 subtract 3 from both sides
2x^2-4x=0 factor
2x(x-2)=0
So x=0 and 2
Step-by-step explanation:
11.
Area of rectangle = 408 in²
Length = 3x-2 and width = x
The area of a rectangle is given by :
A = lb
(3x-2)x = 408
x = 12 inch and x = -11.33 in
Neglecting negative value,
The width of rectangle = 12 inch
The length of rectangle = 3x-2 = 3(12)-2 = 34 inch
12.
Base of triangle = 2x+2
Height = x
The area of a triangle is given by :

x = 24 cm and x = -25 cm
Neglecting negative value, x = 24 cm
Base = 2x+2 = 2(24)+2 = 50 cm
Hence, this is the required solution.
6 + 2 < 9 + 3...u r correct
Correction:
Because F is not present in the statement, instead of working onP(E)P(F) = P(E∩F), I worked on
P(E∩E') = P(E)P(E').
Answer:
The case is not always true.
Step-by-step explanation:
Given that the odds for E equals the odds against E', then it is correct to say that the E and E' do not intersect.
And for any two mutually exclusive events, E and E',
P(E∩E') = 0
Suppose P(E) is not equal to zero, and P(E') is not equal to zero, then
P(E)P(E') cannot be equal to zero.
So
P(E)P(E') ≠ 0
This makes P(E∩E') different from P(E)P(E')
Therefore,
P(E∩E') ≠ P(E)P(E') in this case.