Hat expression is equivalent to (5z^2+3z+2)^2

Mathematics

2 answers:

Lelechka [254]3 years ago

8 0

25z^4+30z^3+29z^2+12z+4

jok3333 [9.3K]3 years ago

3 0

Answer:

$(5z^2+3z+2)^2=25z^4+30z^3+29z^2+12z+4$

Step-by-step explanation:

We have ;

$(5z^2+3z+2)^2=$

$(a+b)^2=a^2+b^2+2ab$

$a = (5z^2+3z)$

b = 2

$=(5z^2+3z)^2+4+2\times (5z^2+3z)\times 2$

$=(25z^4+9z^2+2\times 5z^2\times 3z)+4+4(5z^2+3z)$

$=25z^4+9z^2+30z^3+4+20z^2+12z$

$=25z^4+30z^3+29z^2+12z+4$

So, $(5z^2+3z+2)^2=25z^4+30z^3+29z^2+12z+4$

You might be interested in

1. What is the formula for compound interest?

Rus_ich [418]

Answer:

1. CI = P (1 + $\frac{r}{100}$ )^ n - P

CI = A - P

Where P is Principal

R is interest rate

n is number of years

2. a. Semi annually - four times in a year

b. Monthly - two times in a year

c. annually - once in a year

Step-by-step explanation:

1. Money is said to be lent at compound interest , when the interest has become due at certain fixed period say, one year, half year, etc.., is given not paid to money lender, but is added to sum lent . The amount thus obtained become principal for next month and this process repeat until last period .

i.e CI = Final period - Initial period

or CI = A - P

or CI = P(1+ $\frac{r}{100}$ ) ^n - P

2. (a) Semi annually

A = P (1 + $\frac{r}{4 * 100}$ )^ n × 4