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ale4655 [162]
4 years ago
7

Please help meeeeeeeeeee

Mathematics
1 answer:
vova2212 [387]4 years ago
6 0

Answer:

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Find the area of a square flower garden with the given length of a side. UseA = 52Side = 6 ft
Gennadij [26K]

Answer:

36ft^2

Step-by-step explanation:

We are given that

Side of square,s=6 ft

We have to find the area of square flower garden.

To find the area of square flower garden we will use the formula of area of square.

Area of square=A=Side\times side=s^2

By using the formula then, we get

Area of square flower garden=6\times 6

Area of square flower garden =36 ft^2

Hence, the area of square flower garden=36ft^2

8 0
4 years ago
Which is the correct answer?
larisa [96]

Answer:

a reflection in the y axis followed by a translation 1 unit down

7 0
3 years ago
Read 2 more answers
Write the equation of the graph obtained when the graph of y=1/x is compressed vertically by a factor of 0.25, translated 4 unit
Shtirlitz [24]

Answer: The equation is y = 0.25/(x - 4) + 3

Step-by-step explanation:

If we have a function y = f(x)

A compression means that we multiply the function by a factor smaller than 1.

Then the vertical compression by a factor of 0.25 is:

y = 0.25*f(x)

a translation by A units to the right, means that we need to valuate the function in x - A.

So now we have:

y = 0.25*f(x - 4)

A translation in the y-axis means that we need to add a constant to the equation, then if we tralate it by 3 units up, we have:

y = 0.25*f(x - A) + 3

Then, if f(x) = 1/x

Our new equation is:

y = 0.25/(x - 4) + 3

8 0
3 years ago
Read 2 more answers
1/2 divided by 9/4 ( 11 minus 4/3 )
ivolga24 [154]
The answer for 1/2 divided by 9/4 is 2/9. 
7 0
3 years ago
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Which of the following is a step used in the construction of an equilateral triangle inscribed in a circle?
Ksenya-84 [330]
The one that is a step used in the construction o an equilateral triangle inscribed in a circle would be :
B. draw two line segments connecting the points where the arc intersects the circle and an endpoint of the diameter

hope this helps
8 0
4 years ago
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