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Mariana [72]
3 years ago
10

Match the following items.

Mathematics
1 answer:
max2010maxim [7]3 years ago
3 0

Answer:

1. ∠ABD = 20°.

2.  Arc AB =  140°.

3.  Arc AD =  40°.

Step-by-step explanation:

Given information: ∠ADB = 70°. BD is diameter.

According to Central angle theorem, the central angle from two chosen points A and B on the circle is always twice the inscribed angle from those two points.

By Central angle theorem,

\angle DAB=90^{\circ}

Using angle sum of property in triangle ADB we get,

\angle ADB+\angle DAB+\angle  ABD=180^{\circ}

70^{\circ}+90^{\circ}+\angle  ABD=180^{\circ}

\angle  ABD=20^{\circ}.

Draw a line segment AO.

In triangle AOD, AO=OD, so

\angle ODB=\angle OAD=70^{\circ}

Using angle sum property in triangle AOD,

\angle AOD+\angle ODA+\angle  OAD=180^{\circ}

\angle AOD+70^{\circ}+70^{\circ}=180^{\circ}

\angle AOD=40^{\circ}

Therefore length of arc AD is 40°.

The angle AOD and AOB are supplementary angles.

\angle AOD+\angle AOB=180^{\circ}

40^{\circ}+\angle AOB=180^{\circ}

\angle AOB=140^{\circ}

Therefore length of arc AB is 140°.

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A ship is anchored off a long straight shoreline that runs north and south. From two observation points 16 miles apart on shore,
ELEN [110]
D - the shortest distance from the ship to the shore.
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