Answer:
1. ∠ABD = 20°.
2. Arc AB = 140°.
3. Arc AD = 40°.
Step-by-step explanation:
Given information: ∠ADB = 70°. BD is diameter.
According to Central angle theorem, the central angle from two chosen points A and B on the circle is always twice the inscribed angle from those two points.
By Central angle theorem,

Using angle sum of property in triangle ADB we get,


.
Draw a line segment AO.
In triangle AOD, AO=OD, so

Using angle sum property in triangle AOD,



Therefore length of arc AD is 40°.
The angle AOD and AOB are supplementary angles.



Therefore length of arc AB is 140°.