Strange question, as normally we would not calculate the "area of the tire." A tire has a cross-sectional area, true, but we don't know the outside radius of the tire when it's mounted on the wheel.
We could certainly calculate the area of a circle with radius 8 inches; it's
A = πr^2, or (here) A = π (8 in)^2 = 64π in^2.
The circumference of the wheel (of radius 8 in) is C = 2π*r, or 16π in.
The numerical difference between 64π and 16π is 48π; this makes no sense because we cannot compare area (in^2) to length (in).
If possible, discuss this situatio with your teacher.
Answer:
Step-by-step explanation: 50 x. 10
Answer:
y = 9x + 18
where y is the weight and x is the age
Explanation:
Assume that the age is x and the weight is y.
We are given that:
At age of 16, Logan was 162 pounds. Therefore, point on the line is (16,162)
At age of 20, Logan was 198 pounds. Therefore, point on the line is (20,198)
The general form of the linear equation is:
y = mx + c
where m is the slope and c is the y-intercept
1- getting the slope:
slope (m) = (y2-y1) / (x2-x1)
m = (198-162) / (20-16) = 9
The equation now becomes:
y = 9x + c
2- getting the y-intercept:
The two given points belong to the required line. This means that each of them satisfies the equation of the line.
So, to get the y-intercept, we will substitute with one of the points in the equation and solve for c.
I will use point (16,162) as follows:
y = mx + c
162 = 9(16) + c
162 = 144 + c
c = 162 - 144 = 18
Therefore, the equation becomes:
y = 9x + 18
Hope this helps :)
2(x+1) -3
2(6+1) -3
2(7) -3
14 -3
11
ANSWER IS:
C 11
