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harkovskaia [24]

3 years ago

7

If A(7,9) and B(3,12) find AB (remember: AB means "the distance between points A and B")

1 answer:

GREYUIT [131]3 years ago

5 0

The length of segments ab is 24

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irina1246 [14]

123 rounded to the nearest hundred is 100 i believe

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7% decimal round to the thousands place

nataly862011 [7]

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3 years ago

2(4x-3)>-3(3x)+5x help

Roman55 [17]

Answer:

$x>1/2$

Step-by-step explanation:

$2(4x-3)>-3(3x)+5x$

Expand the brackets.

$8x-6>-9x+5x$

Add -9x and 5x

$8x-6>-4x$

Add 4x and 6x on both sides.

$8x+4x>6$

Add the like terms.

$12x>6$

Divide 12 into both sides.

$12x/12>6/12$

$x>1/2$

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3 years ago

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Bumek [7]

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7 0

3 years ago

In a triangle ABC, measure of angle B is 90 degrees. AB is 3x-2 units and BC is x+3. If the area of the triangle is 17 sq cm, fo

Scorpion4ik [409]

Answer:

$x=\frac{8}{3}\ cm$

Step-by-step explanation:

we know that

The area of the right triangle ABC is equal to

$A=\frac{1}{2}(AB)(BC)$

we have

$A=17\ cm^2$

$AB=(3x-2)\ cm$

$BC=(x+3)\ cm$

substitute the values

$17=\frac{1}{2}(3x-2)(x+3)$

$34=(3x-2)(x+3)$

$34=3x^2+9x-2x-6$

$3x^2+7x-6-34=0$

$3x^2+7x-40=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^2+7x-40=0$

so

$a=3\\b=7\\c=-40$

substitute in the formula

$x=\frac{-7(+/-)\sqrt{7^{2}-4(3)(-40)}} {2(3)}$

$x=\frac{-7(+/-)\sqrt{529}} {6}$

$x=\frac{-7(+/-)23} {6}$

$x=\frac{-7(+)23} {6}=\frac{16}{6}=\frac{8}{3}$

$x=\frac{-7(-)23} {6}=-5$

therefore

The solution is

$x=\frac{8}{3}\ cm$

6 0

3 years ago