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harkovskaia [24]
3 years ago
7

If A(7,9) and B(3,12) find AB (remember: AB means "the distance between points A and B")

Mathematics
1 answer:
GREYUIT [131]3 years ago
5 0
The length of segments ab is 24
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2(4x-3)>-3(3x)+5x help
Roman55 [17]

Answer:

x>1/2

Step-by-step explanation:

2(4x-3)>-3(3x)+5x

Expand the brackets.

8x-6>-9x+5x

Add -9x and 5x

8x-6>-4x

Add 4x and 6x on both sides.

8x+4x>6

Add the like terms.

12x>6

Divide 12 into both sides.

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In a triangle ABC, measure of angle B is 90 degrees. AB is 3x-2 units and BC is x+3. If the area of the triangle is 17 sq cm, fo
Scorpion4ik [409]

Answer:

x=\frac{8}{3}\ cm

Step-by-step explanation:

we know that

The area of the right triangle ABC is equal to

A=\frac{1}{2}(AB)(BC)

we have

A=17\ cm^2

AB=(3x-2)\ cm

BC=(x+3)\ cm

substitute the values

17=\frac{1}{2}(3x-2)(x+3)

34=(3x-2)(x+3)

34=3x^2+9x-2x-6

3x^2+7x-6-34=0

3x^2+7x-40=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

3x^2+7x-40=0

so

a=3\\b=7\\c=-40

substitute in the formula

x=\frac{-7(+/-)\sqrt{7^{2}-4(3)(-40)}} {2(3)}

x=\frac{-7(+/-)\sqrt{529}} {6}

x=\frac{-7(+/-)23} {6}

x=\frac{-7(+)23} {6}=\frac{16}{6}=\frac{8}{3}

x=\frac{-7(-)23} {6}=-5

therefore

The solution is

x=\frac{8}{3}\ cm

6 0
3 years ago
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