<u>Answer:</u> The mass percent of lead in lead (IV) carbonate is 63.32 %
<u>Explanation:</u>
The given chemical formula of lead (IV) carbonate is
To calculate the mass percentage of lead in lead (IV) carbonate, we use the equation:
Mass of lead = (1 × 207.2) = 207.2 g
Mass of lead (IV) carbonate = [(1 × 207.2) + (2 × 12) + (6 × 16)] = 327.2 g
Putting values in above equation, we get:
Hence, the mass percent of lead in lead (IV) carbonate is 63.32 %
Density--<span>1.0g/cm3
Gravity-- </span><span>2.65g/cm3
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All options are as follow,
<span>A. PbS + O2→ PbO + SO</span>₂<span>
B. PbS + 2O</span>₂<span>→ PbO + 2SO</span>₂<span>
C. 2PbS + 2O</span>₂<span>→ 2PbO + 2SO</span>₂<span>
D. 2PbS + 3O</span>₂<span>→ 2PbO + 2SO</span>₂<span>
E. 3PbS + 3O2→ 2PbO + 2SO2
Option A is not balanced because the number of oxygen atoms are greater at right hand side.
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Option B is not balanced because the number of oxygen are less at right hand side and number of sulfur atoms are greater at right hand side.
Option C is not balanced because the number of oxygen atoms are greater at right hand side.
Option D is Balanced, all elements are balanced at both sides.
Option E is not balanced because number of Lead and Sulfur atoms are greater at right hand side.
Result:
Equation in Option D is balanced and correct answer.
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A hydrogen atom is an atom of the chemical element hydrogen. The electrically neutral atom contains a single positively charged proton and a single negatively charged electron bound to the nucleus by the Coulomb force. Atomic hydrogen constitutes about 75% of the baryonic mass of the universe.
Based on the standards of units conversion, to convert from micrometer to meter, we multiply by 10^-6.
Since we there is a square (10^2) to consider, then to convert from micrometer squared to meter squared, we will multiply by (10^-6)^2 as follows:
1.5 <span>μm2 = 1.5 x (10^-6)^2 = 1.5 x 10^-12 meter sqaures</span>