43.56 grams of are produced if 16g of CH4 reacts with 64g of O2.
Explanation:
Balance equation for the reaction:
CH4 + 2O2⇒ CO2 +2H2O
Data given : mass of CH4 =16 grams atomic mass = 16.04 grams/mole
mass of water 36 gram atomic mass = 18 grams/moles
mass of CO2=? atomic mass = 44.01 grams/mole
number of moles =
equation 1
number of moles in CH4
n = 
= 0.99 moles
Since combustion is done in presence of oxygen hence it is an excess reagent and methane is limiting reagent so production of CO2 depends on it.
From the equation
1 mole of CH4 gave 1 mole of CO2
O.99 moles of CH4 will give x moles of CO2
= 
x = 0.99 moles of carbon dioxide
grams of CO2 = number of moles x atomic mass
= 0.99 x 44.01
= 43.56 grams of CO2 is produced.
Answer : The electrons in a bond between two iodine atoms are shared equally and non-polar.
Explanation :
Non-polar covalent bond : It is a type of bond that is present between the two similar and different atoms. This type of bond is formed when the electrons are shared equally between the atoms.
This type of bond is termed as non-polar because of the electronegativity difference between the atoms is negligible.
The given molecule
is formed by the equal sharing of electrons and the bond formed between the iodine-iodine is non-polar due to negligible electronegativity difference.
Therefore, the electrons in a bond between two iodine atoms are shared equally and non-polar.
Answer:
a b c are correct and rest of other are incorrect
Answer:
Specific rotation of cholesterol is -3.15°.
Explanation:
Given that
Path length = 10 cm = 1 dm.
Observed rotation ,α= - 0.441 °
m= 0.14 g
V= 1 ml
The concentration of cholesterol ,c= m/V g/ml
c = 0.14 / 1 = 0.14 g/ml
We know that specific rotation given as
![[\alpha]_D=\dfrac{\alpha}{l.c}](https://tex.z-dn.net/?f=%5B%5Calpha%5D_D%3D%5Cdfrac%7B%5Calpha%7D%7Bl.c%7D)
Now by putting the all values
![[\alpha]_D=\dfrac{\alpha}{l.c}](https://tex.z-dn.net/?f=%5B%5Calpha%5D_D%3D%5Cdfrac%7B%5Calpha%7D%7Bl.c%7D)
![[\alpha]_D=\dfrac{-0.441}{1\times 0.14}](https://tex.z-dn.net/?f=%5B%5Calpha%5D_D%3D%5Cdfrac%7B-0.441%7D%7B1%5Ctimes%200.14%7D)
°
Specific rotation of cholesterol is -3.15°.