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zvonat [6]
3 years ago
7

the elements fluorine,chlorine,bromine,and iodine are all found in the same group on the table. these elements are grouped toget

her because they​

Chemistry
2 answers:
madreJ [45]3 years ago
8 0

Answer:

Fluorine, chlorine, bromine and iodine are grouped together because they have the same number of valence electrons.

Explanation:

Fluorine, chlorine, bromine and iodine are all found in group 7, which is the second-last column from the right. Group 7 elements are also called the "Halogens" family.

The group number also tells you the number of valence electrons that the elements have in that group. Valence electrons mean the outermost electrons (See picture).

For example, fluorine has two shells (the circles with dots on them). The outermost electrons, or valence electrons, are the dots on the biggest circle. There are 7 dots, so there are 7 valence electrons, which corresponds with Group "7".

A full shell (except the for first shell) is when there are 8 dots. Since 7 is so close to 8, Halogens are very reactive.

Fluorine, chlorine, bromine and iodine all have 7 valence electrons and are in the Halogens family, which are very reactive.

RideAnS [48]3 years ago
8 0

Answer: Have the same valence electrons

Explanation: These elements are found in group 7 which indicates the number of valence electrons in their outermost shell.

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If the absorbance of a solution of curcumin which is too concentrated is measured, the absorbance will be unusually high.

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Hence, if  the absorbance of a solution of curcumin which is too concentrated is measured, the absorbance will be unusually high. An unusually high absorbance tells us that the solution is too concentrated.

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What is the h+ concentration for an aqueous solution with poh = 3.35 at 25 ∘c? express your answer to two significant figures an
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POH value was calculated by the negative logarithm of hydroxide ion concentration.
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Identify the double displacement reaction. 3Pb 2h 3PO 4 ⟶ 3H 2 Pb 3(PO 4) 2 2NO 2 ⟶ 2O 2 N 2 2NaBr Ca(OH) 2 ⟶ CaBr 2 2NaOH 2NH 3
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Reaction 3 is the double displacement reaction.

Double displacement reaction occurs when the negatively and the positively charged ions of the compounds interchange their position when the new compound in the product is formed.

<h3>Which is a double displacement reaction?</h3>

In the <u>first reaction</u>, the element lead (Pb) is not an ion and no exchange of the cations or the anions occurs hence it is not a double displacement reaction.

In the <u>second reaction</u>, one compound is getting split into two new compounds and is a decomposition reaction.

In the <u>third reaction</u>,  \rm Br^{-} in \rm 2NaBr and \rm (OH)_{2} in \rm Ca(OH)_{2} are anions and cations and exchanges their places to produce two new compounds  \rm CaBr_{2} + 2NaOH.

In the <u>fourth reaction</u>, a single compound is generated as the result of the combination reaction and hence, it is not the double displacement reaction.

Therefore, \rm 2NaBr + Ca(OH)_{2} \rightarrow CaBr_{2} + 2NaOH is the double displacement reaction.

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