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taurus [48]
3 years ago
7

the radius of the white circle is 4cm and the radius of the grey circle is an additional 3cm what is the area of the grey region

only​
Mathematics
1 answer:
pickupchik [31]3 years ago
6 0

Answer:

103.62 cm squared :)

Step-by-step explanation:

To solve this problem, lets start with the grey area only and essentially we want to treat it like it's own circle. So the formula for circular area is A=pi times r²

so for the radius of the grey region, we will simply add 3 and 4 cm.

3+4=7cm

Then we can plug that into the area equation, which is:

A = (3.14)(7²)

Solve for that and we should get 153.86 cm²

We'll hold onto that for now while we solve for the white circle next:

A = (3.14) (4²)

A = 50.24cm²

Lastly, let's bring back the grey area we found earlier, and subtract the white area from it:

153.86 - 50.24 = 103.62 cm²

hope this helps and good luck~

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It is called "Pythagoras' Theorem" and can be written in one short equation:

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Answer:

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b) The surface area of the prism is 514 mm²

Step-by-step explanation:

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a) To find the volume, we can consider the prism as a composite figure as follows;

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Therefore, the volume of the topmost cuboid, V₁, is given as follows;

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The volume of the cuboid on which the top cuboid rest, V₂, is given as follows;

V₂ = 15 mm × 5 mm × 7 mm = 525 mm³

The volume of the prism, V = V₁ + V₂

Therefore, we have;

V =135 mm³ + 525 mm³ = 660 mm³

The volume of the prism, V = 660 mm³

b) The surface area of the prism is given as follows;

The surface area of the top cuboid, SA₁, is given as follows;

SA₁ = 9 mm × 5 mm + 2 × 3 mm × 9 mm + 2 × 3 mm × 5 mm = 129 mm²

The surface area of the larger cuboid, SA₂, is given as follows;

SA₂ = 2 × 15 mm × 7 mm + 2 × 5 mm × 7 mm + 2 × 3 mm × 5 mm + 15 mm × 5 mm = 385 mm²

The surface area of the prism, SA = SA₁ + SA₂

∴ The surface area of the prism, SA = 129 mm² + 385 mm² = 514 mm²

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