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makkiz [27]
3 years ago
12

give the coordinates (-6,5) and (4,-8) find the distance between the two points. Round your answer to the nearest tenth

Mathematics
1 answer:
scoundrel [369]3 years ago
5 0

Answer:

16.4

Step-by-step explanation:

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Solve for b; 5ba - x = y
saul85 [17]

Answer and Step-by-step explanation:

<u>First, add x to both sides.</u>

5ba = x + y

<u>Now, divide both sides by 5a.</u>

<u></u>b = \frac{x+ y}{5a}<u> is the answer.</u>

<u></u>

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<em><u>#teamtrees #PAW (Plant And Water)</u></em>

3 0
3 years ago
John scored 17 out of 30 in the Entrepreneurship test calculate his marks in percentage give your answer to one decimal place​
Vesnalui [34]

Answer:

well, one john isnt that smart . he scored a 57% (0.5666....repeating)

Step-by-step explanation:

17 divided by

30

4 0
3 years ago
What is the difference of the polynomials? (8r^6s^3 – 9r^5s^4 + 3r^4s^5) – (2r^4s^5 – 5r^3s^6 – 4r^5s^4)
Dafna1 [17]
<span>(8r^6s^3 – 9r^5s^4 + 3r^4s^5) – (2r^4s^5 – 5r^3s^6 – 4r^5s^4)
= </span><span>8r^6s^3 – 9r^5s^4 + 3r^4s^5 – 2r^4s^5 +  5r^3s^6 + 4r^5s^4
= </span>8r^6s^3 – 9r^5s^4 +  4r^5s^4 + 3r^4s^5 – 2r^4s^5 +  5r^3s^6 
= 8r^6s^3 – 5r^5s^4 + r^4s^5  +  5r^3s^6 

Hope it helps
4 0
4 years ago
Read 2 more answers
Find are of shaded region?
castortr0y [4]
Ignoring the triangle first off, it is just a parallelogram. We can find the area with:
A_{P}=b*h=23.8 * 15=357 square ft. (see first diagram).

Next, we need to find the area of the triangle. Its a right angle triangle, so the area can be found by:
A_{T} = \frac{1}{2} wl
where w and l are the lengths of the two smaller sides. We have one, and the longer side (hypotenuse) so we can use Pythagoras' Theorem to find the other small side (see second diagram).
b= \sqrt{ a^{2} - c^{2} } =\sqrt{ 23.8^{2} - 21^{2} }=11.2ft.
Then find the area:
A_{T} =0.5*21*11.2=117.6 square ft.

Take the area of the triangle away from the area of the paralellogram:
357-117.6=239.4 ft^{2}

7 0
3 years ago
What is c/6=9 equals to
Julli [10]

c = 54

!!!_!£((£2((2)1)1)1

5 0
3 years ago
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