Find the diagonal length of this figure
2 answers:
Answer:
![5\sqrt{5} \:mm](https://tex.z-dn.net/?f=5%5Csqrt%7B5%7D%20%5C%3Amm)
or
11.18 mm
Step-by-step explanation:
length of diagonal
![=\sqrt{l^{2} +w^{2}+h^{2} } \\=\sqrt{8^{2} +6^{2}+5^{2} } \\=\sqrt{64 +36+25 } \\=\sqrt{125 } \\=5\sqrt{5} \: mm\\=11.18 mm](https://tex.z-dn.net/?f=%3D%5Csqrt%7Bl%5E%7B2%7D%20%2Bw%5E%7B2%7D%2Bh%5E%7B2%7D%20%20%7D%20%5C%5C%3D%5Csqrt%7B8%5E%7B2%7D%20%2B6%5E%7B2%7D%2B5%5E%7B2%7D%20%20%7D%20%5C%5C%3D%5Csqrt%7B64%20%2B36%2B25%20%7D%20%5C%5C%3D%5Csqrt%7B125%20%7D%20%5C%5C%3D5%5Csqrt%7B5%7D%20%5C%3A%20mm%5C%5C%3D11.18%20mm)
Answer:
the answer is,
11.18mm
by pythagoras theorem, you'll get base diagonal as 10mm, therefore the diagonal*marked red is 11.18mm.
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