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Marysya12 [62]
3 years ago
11

Descubra a lei ou regra da função do tipo f(x) = ax + bx + c no gráfico

Mathematics
1 answer:
Sholpan [36]3 years ago
7 0
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Mr. Patrick teaches math to 1515 students.
katrin2010 [14]
Sum of all grades / number of students = average grade

Average grade = 80
number of students = 1514 (excluding payton)

80 * 1514 = 121120

Average grade = 81
number of students = 1515

81 * 1515 = 122715

Sum of 1515 students = 122715
Sum of 1514 students = <u>121120</u>
Difference:                          1595   *Paytons grade

7 0
3 years ago
What are the solutions to the equation 3x^2 + 15x = 18. Show your work.
balandron [24]

Assignment: \bold{Solve \ Equation: \ 3x^2+15x=18}

<><><><><><><>

Answer: \boxed{\bold{x=1,\:x=-6}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><><><>

[ Step One ] Subtract 18 From Both Sides

\bold{3x^2+15x-18=18-18}

[ Step Two ] Simplify

\bold{3x^2+15x-18=0}

[ Step Three ] Solve With Quadratic Formula

Note: \bold{For\:a\:quadratic\:equation\:of\:the\:form\: ax^2+bx+c=0}

\bold{the \ solutions \ are \ x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}}

\bold{a=3,\:b=15,\:c=-18:\quad x_{1,\:2}=\frac{-15\pm \sqrt{15^2-4\cdot \:3\left(-18\right)}}{2\cdot \:3}}

<><><><><><><>

\bold{\frac{-15+\sqrt{15^2-4\cdot \:3\left(-18\right)}}{2\cdot \:3}: \ 1}

\bold{\frac{-15-\sqrt{15^2-4\cdot \:3\left(-18\right)}}{2\cdot \:3}: \ -6}

[ Step Four ] Combine Solutions

\bold{x=1,\:x=-6}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

5 0
2 years ago
Read 2 more answers
5/12+8/12 I need help
Ronch [10]

\frac{13}{12} is the answer

Hope this helps

6 0
3 years ago
Read 2 more answers
If you could please help ASAP it would be greatly appreciated!
klemol [59]

Answer:

A. 20

Step-by-step explanation:

because she has twice as many and if you have twice as many then you'll have 40 so 40+20=60

5 0
3 years ago
Read 2 more answers
CALC BC HELPPP!!!??? 100PTS!!!
lyudmila [28]

the assumption being that "x" is a plain variable whilst "y" is a function, that matters because the chain rule would be needed for a function, not so for a plain variable.

4x^2+4x+xy=5\implies 8x+4+\stackrel{\textit{product rule}}{\left( 1\cdot y+x\cdot \cfrac{dy}{dx} \right)}=0 \\\\\\ x\cfrac{dy}{dx}=-8x-4-y\implies \cfrac{dy}{dx}=\cfrac{-8x-4-y}{x}

now, we know that y(5) = -23, which is another way of saying that when x = 5, y = -23, but we already knew that, we can get that by simply plugging it into the equation hmmm y'(5), well

\left. \cfrac{dy}{dx}=\cfrac{-8x-4-y}{x} \right|_{\stackrel{x=5~}{\textit{\tiny y=-23}}}\implies \cfrac{-8(5)-4-(-23)}{5}\implies \cfrac{-21}{5}

8 0
2 years ago
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