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Serhud [2]
3 years ago
6

Can someone help me? And no, I don’t just want the answer. I literally need to know how to do it pls

Mathematics
1 answer:
elena-s [515]3 years ago
7 0

Answer:

36

Step-by-step explanation:

The angle b is a right angle which is divided into 2. So, each angle would measure 45 degree. (90 / 2 = 45)

tan 45 = 1

\AD\ = 100 - 64 = 36

to find x , remember SOCAHTOA

tan would be used because we have the vale of the opposite angle and we want to find the value of the adjacent angle

Tan 45 = opposite / adjacent

1 = 36/x

x = 36

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X^3+y^3=???????????????
omeli [17]

Answer:

Well since we don't know what X or Y is, then we can't answer this question.

Step-by-step explanation:

6 0
3 years ago
Using the numbers 3, 2, and 4, which of these problems would have a solution of 4?
Alexeev081 [22]
Pemdas

ok if we look at the first one
exponents first
2^3=8
2^3=8
we have
4*8/8
4*8=32
32/8=4
das is answer


the first one is the answer
7 0
3 years ago
Sean and Leah are playing a computer game. Sean scored 72,491points. Leah scored 19,326 points more than Sean.How many points di
natita [175]
72,491 + 19,326 = 91,817
Leah scored 91,817 points
4 0
3 years ago
Read 2 more answers
3. (02.01)
sashaice [31]

Answer:

A. 1

Step-by-step explanation:

3(x+1)=-2(x-1)+6

3x+3=2x-2+6

x+3=4

x=1

7 0
3 years ago
Find, corrrect to the nearest degree, the three angles of the triangle with the given vertices. A(1,0), B(3,6), C(-1,4)
Karo-lina-s [1.5K]

Answer:

45°, 45°, 90°

Step-by-step explanation:

Find the vectors to represent each sides

AB =<3-1, 6-0>=<2,6>  

AC = < -1-1, 4 - 0 > = < -2, 4>

Magnitude of the vectors

AB = √(2²+6²) = 6.32

AC = √ ((-2)² + 4²) = 4.47

cosθ = vector of AB × vector AC / ( Product of the magnitude of AB and AC) = 2 × (-2) + (6×4)/ (6.32×4.47) = 20 / 28.2504

θ = arcos(20 / 28.2504 ) approx = 45°

Magnitude of the vectors

BA =<1-3,0-6>=<-2,-6>

BC =<-1-3,4-6>=<-4,-2>

Magnitude of the vectors equals

BA = √((-2)² + (-6)²) = 6.325

BC = √((-4)² + (-2)²) = 4.4721

cosθ = (-2×-4) + (-6 ×-2) / (6.325 × 4.4721) = 20 / 28.286

θ  = arcos (20 / 28.286 ) = 45°

Magnitude of the vectors

CB =<3--1, 6-4>=<4,2>

CA=<1--1,0-4>=<2,-4>

Magnitude of the vector =

CB = √(4² + 2²) = 4.4721

CA = √(2² + (-4)²) = 4.4721

cosθ = (4×2) + (2×-4) / (4.4721×4.4721) = 0

θ = arcos 0 = 90°

4 0
3 years ago
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