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Artyom0805 [142]
3 years ago
11

Which equation can be used to find the measurement of ∠C? To the nearest degree, what is the measurement of ∠A? A) 5sin∠C = 2; 2

4° B) 29 sin∠C = 2; 68° C) 5sin∠C = 29 ; 22° Eliminate D) 29 sin∠C = 2; 22°

Mathematics
2 answers:
finlep [7]3 years ago
8 0

Answer:

Option B

\sqrt{29}sin(C)=2  

A=68\°

Step-by-step explanation:

see the attached figure to better understand the problem

Part A) Which equation can be used to find the measurement of ∠C?

we know that

In the right triangle ABC

sin(C)=\frac{2}{\sqrt{29}}

therefore

\sqrt{29}sin(C)=2  

Part B) What is the measurement of ∠A?

In the right triangle ABC

tan(A)=\frac{5}{2}

A=arctan(\frac{5}{2})=68\°

egoroff_w [7]3 years ago
7 0
First guy is incorrect.Answer is actually B

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Longhorn Corporation provides low-cost food delivery services to senior citizens. At the end of the year on December 31, 2021, t
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The statement of stockholders’ equity for Longhorn Corporation is: $62,800

                                                           

<h3> Statement of stockholders’ equity</h3>

                        Common stock   Retained earning Total stakeholder equity

Beginning balance           $36,000    $17,400        $53,400              

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Ending balance                      $40,000    $22,800      $62,800

Therefore the statement of stockholders’ equity for Longhorn Corporation is: $62,800.

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4 0
2 years ago
Jonas and Mallory are selling bags of cotton candy at the football game. They get paid $20 per game in $2.25 for each bag of cot
Olegator [25]

Answer:

41 bags.

Step-by-step explanation:

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3 years ago
In the equation y=2x+1 what is true about the slope
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Find the absolute maximum and minimum values of the following functions on the given curves functions:
bagirrra123 [75]

Answer:

Solution has explained below:

Step-by-step explanation:

(a) f(x,y) = x+y

To find out the maximum and minimum values, we need to find first and second derivatives, we have

fx= 1, fx₁=0 and

fy= 1 and fyy=0

For stationary points fx=fy=0, which gives,

1=1=0, so that there is just one stationary point, (x,y)=(0,0)

If  fx₁  < 0 and fyy < 0, function is maximum

If  fx₁ > 0 and fyy > 0, function is minimum.

(b) g(x,y) = xy

Sol: To find out the maximum and minimum values, we need to find first and second derivatives, we have

fx= 1 and fy  = 1

fx₁ = 0 and fyy =0

for stationary points fx = fy =0, which gives 1=1=0, so that there is just one stationary points, (x,y) =(0,0)

If fx₁ < 0 and fyy < 0, function is maximum.

If  fx₁  > 0 and fyy> 0, function is minimum.

c) h(x,y) = 2x2 + y2

sol: To find out the maximum and minimum values, we need to find first and second derivatives, we have

fx = 4x  and fy = 2y

fx₁= 4  and fyy = 2

Now, taking fx = 0 and fy = 0

Gives x=0 and y=0,

Stationary points are (x,y) = (0,0)

If fx₁ < 0 and fyy < 0, solution is maximum,

If fx₁ > 0 and fyy > 0, solution is minimum,

Here, fx₁ = 4 > 0 and fyy = 2 > 0.

6 0
3 years ago
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