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Ludmilka [50]
4 years ago
11

What does the release or absorption of energy indicate?

Physics
1 answer:
stich3 [128]4 years ago
5 0

Answer:

The release or absorption of energy indicates a chemical change.

Explanation:

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One or more neutrons in the nucleus add mass to the atom.
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A car of weight 6,400 N has four wheels. Each wheel has an area of
Natasha2012 [34]

Answer:

80N/cm^2

Explanation:

Given data

A car of weight 6,400N

Area= 80cm^2

The weight is distributed evenly on the 4 wheels

hence 6400/4

=1600 N

We know that

Pressure = force/Area

Pressure= 1600/80

Pressure= 20 N/cm^2

For the four wheels, the pressure is

=20*4

=80N/cm^2

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3 years ago
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podryga [215]
The first one is the correct one
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A motorcycle starts at rest and accelerates at a rate of 3 meters per second squared (m/s2) over a time period of 5 seconds (s).
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Final velocity = 3 x 5 = 15 m/s
5 0
3 years ago
Listed following are several fictitious stars with their luminosities given in terms of the Sun's luminosity (LSun) and their di
vova2212 [387]

Answer:

1. Nismo: L_{a}=0.1244

2. Ferdinand: L_{a}=0.0796, Shelby: L_{a}=0.0796

3. Enzo: L_{a}=0.0398

4. Lotus: L_{a}=0.0199

Explanation:

The luminosity of a star is the amount of light it emits from its surface. The luminosity is an intrinsic property of the star. Apparent brightness is how bright the star appears to a detector on Earth. Apparent brightness is not an intrinsic property of the star; it depends on the location of the observer.

As light travels towards an observer, it spreads out and covers a larger area, reducing the intensity. Thus the apparent brightness is inversely proportionate to the square of the distance between the star and observer.

Apparent brightness can be calculated by the formula below:

L_{a}=\frac{L}{4*pi*D^{2}}

Where, L_{a} is apparent brightness, L is luminosity, D is the distance between the star and observer

Enzo: 200 LSun , 20 ly

L_{a}=\frac{L}{4*pi*D^{2}}

L_{a}=\frac{200}{4*pi*20^{2}}

L_{a}=0.0398

Ferdinand: 400 LSun , 20 ly

L_{a}=\frac{L}{4*pi*D^{2}}

L_{a}=\frac{400}{4*pi*20^{2}}

L_{a}=0.0796

Nismo: 100 LSun , 8 ly

L_{a}=\frac{L}{4*pi*D^{2}}

L_{a}=\frac{100}{4*pi*8^{2}}

L_{a}=0.1244

Lotus: 400 LSun , 40 ly

L_{a}=\frac{L}{4*pi*D^{2}}

L_{a}=\frac{400}{4*pi*40^{2}}

L_{a}=0.0199

Shelby: 100 LSun , 10 ly

L_{a}=\frac{L}{4*pi*D^{2}}

L_{a}=\frac{100}{4*pi*10^{2}}

L_{a}=0.0796

Apparent brightness of stars is summarized as below. Absolute values are considered as units are unspecified

Enzo: L_{a}=0.0398

Ferdinand: L_{a}=0.0796

Nismo: L_{a}=0.1244

Lotus: L_{a}=0.0199

Shelby: L_{a}=0.0796

Organized in order of apparent brightness

1. Nismo: L_{a}=0.1244

2. Ferdinand: L_{a}=0.0796, Shelby: L_{a}=0.0796

3. Enzo: L_{a}=0.0398

4. Lotus: L_{a}=0.0199

5 0
3 years ago
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