How many full length strands of hair are collected from the scalp to use as a sample?

Critical reasoning: We also use simulation to understand how the software would behave in the event of potential collisions. Giv

jeka94

Using kinematic reasoning, the answers for the changes that can cause crashes are:

we can manipulate

The speed of the vehicles, especially that of the second car

he traffic light change time

Change some condition of the pavement after the first vehicle passes

Autonomous systems are systems that take a series of signals from the outside, analyze them and carry out actions according to how to handle them.

In that case you have two cars one behind the other at a short distance a traffic light with a yellow light is approaching.

Some parameters can be modified to cause the crash:

The car in front accelerates to pass the traffic light, but the traffic light changed to red, in this case if the car behind also accelerated, there may not be enough distance to stop and crash.

You can change the traffic light to green whereby the first car continues its speed, but the traffic light time changes very quickly to red, whereby the first car stops, but the car behind cannot stop.

The car behind accelerates to also pass the yellow light, but turns red and the first one crashes to a stop.

We change some condition of the pavement after the first vehicle passes, for example wetting the pavement, which decreases the coefficient of friction, consequently the second vehicle does not have time to stop.

We can appreciate that if there is not a good and fast communication between the two vehicles, it is easy for them to crash.

In conclusion, using kinematic reasoning, the answers for the changes that can test shocks are found:

The second vehicle increases speed and the first must brake sharply

Learn more about stopping distance here:

brainly.com/question/24254597

6 0

2 years ago

Switches, flashers, and similar devices controlling transformers and electronic power supplies shall be rated for controlling in

Reika [66]

Answer:

Option A - twice

Explanation:

5 0

3 years ago

A racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction). It hits the wall of th

zheka24 [161]

The magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

Given that a racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction).

mass m = 42g = 42/1000 = 0.042kg

initial velocity before collision u = 7 m/s

It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/s to the left (-x direction). That is,

velocity after collision v = 7 m/s

To calculate the magnitude of the racquetball's change in momentum, we will use the formula below

Change in momentum = Mv - Mu

Since momentum is a vector quantity, we will consider the direction.

Change in momentum = 0.042 x 7 - ( 0.042 x - 7)

Change in momentum = 0.294 + 0.294

Change in momentum = 0.588 kgm/s

Therefore, the magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

Learn more on momentum here: brainly.com/question/402617

5 0

2 years ago

What is the net torque on the square plate, with sides 0.2 m, from each of the three forces? F1=18 N, F2=26 N, and F3=14 N. Use

marshall27 [118]

Answer:

The net torque on the square plate is 2.72 N-m.

Explanation:

Given that,

Side = 0.2 m

Force $F_{1}=18\ N$

Force $F_{2}=26\ N$

Force $F_{3}=14\ N$

We need to calculate the torque due to force F₁

Using formula of torque

$\tau_{1}=-F_{1}d_{1}$

$\tau_{1}=-F_{1}\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{1}=-18\times\dfrac{0.2}{2}$

$\tau_{1}=-1.8\ N-m$

We need to calculate the torque due to force F₂

Using formula of torque

$\tau_{2}=F_{2}d_{2}$

$\tau_{2}=F_{2}\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{2}=26\times\dfrac{0.2}{2}$

$\tau_{2}=2.6\ N-m$

We need to calculate the torque due to force F₃

Using formula of torque

$\tau_{3}=F_{3}d_{3}$

$\tau_{3}=(F_{3}\sin45+F_{3}\cos45)\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{3}=0.1(14\sin45+14\cos45)$

$\tau_{3}=1.92\ N-m$

We need to calculate the net torque on the square plate

$\tau=\tau_{1}+\tau_{2}+\tau_{3}$

$\tau=-1.8+2.6+1.92$

$\tau=2.72\ N-m$

Hence, The net torque on the square plate is 2.72 N-m.

3 0

3 years ago

Question 1 and 2 and 3 physics lesson homework

storchak [24]

Answer:

Jackson 2: Smart 3: Ahmed

Explanation:

square + circle = egg

oops, wrong guy

5 0

2 years ago