An object is dropped at a height of 6 m from the ground. How fast is it moving just before it hits the ground?
1 answer:
Explanation:
Given:
Δy = 6 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: v
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (9.8 m/s²) (6 m)
v ≈ 10.8 m/s
Round as needed.
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Its the same thing. Is 250 grams more then 100 grams
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