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2 years ago

Whats 5 plus 6, i cant find out, its hard

Mathematics

2 answers:

NNADVOKAT [17]2 years ago

4 0

5+6= 11 , good luck

katrin [286]2 years ago

3 0

Answer:

its 11

Step-by-step explanation:

because when you add 6 and 5 your answer will be 11 and its very easy and clear

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In the slope - intercept equation of a line which quantity is given by the coefficient of the term x-term?

Kamila [148]

I believe it is the x slope

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3 years ago

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Evaluate the expression 3+ [5(2-3) - 6]

iragen [17]

Answer:

Answer is below

Step-by-step explanation:

3+5(2−3)−6

=3+(5)(−1)−6

=3+−5−6

=3+−11

=−8

So therefore, your answer would be -8

8 0

3 years ago

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The answer appears incorrect, please help me correct it :)

UNO [17]

Every line on the graph is 1/2 unit.

When y = 0, x would be -0.25 and 1.25

When y = 2, x would be -0.5 and 1.5

4 0

3 years ago

If x>2,then x2-x-6/x2-4=

statuscvo [17]

$\frac{x^2-x-6}{x^2-4}=(*)\\------------\\x^2-x-6=0\\a=1;\ b=-1;\ c=-6\\\Delta=b^2-4ac;\ \Delta=(-1)^2-4\cdot1\cdot(-6)=1+24=25\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\x_1=\frac{1-\sqrt{25}}{2\cdot1}=\frac{1-5}{2}=\frac{-4}{2}=-2\\\\x_2=\frac{1+\sqrt{25}}{2\cdot1}=\frac{1+5}{2}=\frac{6}{2}=3\\\\x^2-x-6=(x+2)(x-3)$
$---------------------\\x^2-4=x^2-2^2=(x-2)(x+2)\\-------------------\\\\(*)=\frac{(x+2)(x-3)}{(x-2)(x+2)}=\frac{x-3}{x-2}$

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3 years ago

What is the initial value.

GrogVix [38]

The function shown in the graph is a linear function, for a given linear function, the initial value is obtained at y-intercept. The y-intercept is the point where the graph cuts the y-axis. At this point the value of x is zero. Thus from the graph given, the point x=0 at y=2, hence the initial value is y=2.
Answer: y=2

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3 years ago