Answer:
(x+8)^2=0
Step-by-step explanation:
x^2+16x+64=0
8x8=64
8+8=16
Therefore, 8 fits
(x+8)^2=0
If this helps please mark as brainliest
To find it, evaluate it at the endpoints and the vertex
in form
f(x)=ax²+bx+c
the x value of the vertex is -b/2a
given
c(t)=1t²-10t+76
x value of vertex is -(-10)/1=10
evaluate c(0) and c(13) and c(10)
c(0)=76
c(13)=115
c(10)=76
it reached minimum in 2000 and 2010
porbably teacher wants 2010
the min value is $76
Answer:
The larger integer is 
.
Step-by-step explanation:
Given: Two times the smaller of two consecutive integers is equal to 
more than the larger.
To find: The larger integer.
Solution:
Let the two consecutive integers be 
and 
, where the smaller integer is and larger integer is .
Now, according to question.
Two times the smaller integer 
more than the larger integer.
So, the smaller integer is 
, and the larger integer is 
Hence, the larger integer is 
Answer:
770000
Step-by-step explanation:
im not sure
