Answer:
The number of minutes advertisement should use is found.
x ≅ 12 mins
Step-by-step explanation:
(MISSING PART OF THE QUESTION: AVERAGE WAITING TIME = 2.5 MINUTES)
<h3 /><h3>Step 1</h3>
For such problems, we can use probability density function, in which probability is found out by taking integral of a function across an interval.
Probability Density Function is given by:

Consider the second function:

Where Average waiting time = μ = 2.5
The function f(t) becomes

<h3>Step 2</h3>
The manager wants to give free hamburgers to only 1% of her costumers, which means that probability of a costumer getting a free hamburger is 0.01
The probability that a costumer has to wait for more than x minutes is:

which is equal to 0.01
<h3>
Step 3</h3>
Solve the equation for x

Take natural log on both sides

<h3>Results</h3>
The costumer has to wait x = 11.53 mins ≅ 12 mins to get a free hamburger
Answer:
Use the distance formula to determine the distance between the two points.
Distance
=
√(x2−x1)^2 + (y2−y1)^2
Substitute the actual values of the points into the distance formula.
√ ( (−6) − 0)^2 +( (−3) − 4)^2
Subtract 0 from −6
√(−6)^2 + ( ( −3 ) −4 )^2
Raise −6 to the power of 2
√36 + ( ( −3 ) −4 )^2
Subtract 4 from −3
√36 + ( −7 )^2
Raise −7 to the power of 2
√ 36 + 49
Add 36 and 49
√85
A)
<span>|x + y = 5 </span>
<span>|2x - y = 7; </span>
<span>b) </span>
<span>|2x + y = 5 </span>
<span>|x - y = 2 </span>
<span>c) </span>
<span>|3x + y = 6 </span>
<span>|4x - 3y = -5 </span>
<span>d) </span>
<span>|1/(x - 1) = y - 3 </span>
<span>|x - y = -2 </span>
<span>e) </span>
<span>|(9x + 4y)/3 - (5x - 11)/2 = 13 - y </span>
<span>|13x - 7y = -8 </span>
<span>Answer: </span>c<span> and </span>e<span> has solution (1; 3)</span>
Answer:
V'(t) = 
If we know the time, we can plug in the value for "t" in the above derivative and find how much water drained for the given point of t.
Step-by-step explanation:
Given:
V =
, where 0≤t≤40.
Here we have to find the derivative with respect to "t"
We have to use the chain rule to find the derivative.
V'(t) = 
V'(t) = 
When we simplify the above, we get
V'(t) = 
If we know the time, we can plug in the value for "t" and find how much water drained for the given point of t.