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3 years ago

POH is a measure of the ________________ in solution. *

Chemistry

1 answer:

Digiron [165]3 years ago

3 0

Answer:

Both acids and bases can measured using the pH or pOH scale. Both scales provide a measure of either the H+ concentration or the OH- concentration. Notice that each scale shows were acids and bases both are located. When acids are measured, the pH is less than 7, but the pOH is greater than 7.

Explanation:

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Equation balancing a. S(s) + O2(g) → SO3(8) b. 2Al(s) + 3C12(8) ► 2AICI,(s) E. 2NaOH(s) + H2SO,(ac) —Na,SO (ac) + H2O(1) d. CHg(

Debora [2.8K]

Answer:

a. S(s) + 3/2 O₂(g) → SO₃(g)

b. Al(s) + 3/2 Cl₂(g) → AICI₃(s)

c. 2 NaOH(s) + H₂SO₄(ac) → Na₂SO₄(ac) + 2 H₂O(l)

d. C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)

Explanation:

We will balance the equation using the trial and error method.

a. S(s) + O₂(g) → SO₃(g)

1. We will balance O atoms by multiplying O₂by 3/2.

S(s) + 3/2 O₂(g) → SO₃(g)

b. Al(s) + Cl₂(g) → AICI₃(s)

1. We will balance Cl atoms by multiplying Cl₂ by 3/2.

Al(s) + 3/2 Cl₂(g) → AICI₃(s)

c. NaOH(s) + H₂SO₄(ac) → Na₂SO₄(ac) + H₂O(l)

1. We will balance Na atoms by multiplying NaOH by 2.

2. We will balance H and O atoms by multiplying H₂O by 2.

2 NaOH(s) + H₂SO₄(ac) → Na₂SO₄(ac) + 2 H₂O(l)

d. C₃H₈(g) + O₂(g) → CO₂(g) + H₂O(g)

1. We will balance C atoms by multiplying CO₂ by 3.

2. We will balance H atoms by multiplying H₂O by 4.

3. We will balance O atoms by multiplying O₂ by 5.

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)

8 0

3 years ago

Air enters a diffuser witha velocity of 400 m/s, a pressure of 1 bar and temperature of 25 C. It exits with a temperature of 100

ANEK [815]

Answer:

Exit velocity of air is 96.43 m/s.

Explanation:

Given that

$V_1=400\ m/s$

$T_1=25C$

$T_2=100C$

For air

$C_p=1.005\ KJ/kg.K$

Now from first law of thermodynamics for open system at steady state

$h_1+\dfrac{V_1^2}{2000}+Q=h_2+\dfrac{V_2^2}{2000}+w$

For diffuser

$h_1+\dfrac{V_1^2}{2000}=h_2+\dfrac{V_2^2}{2000}$

We know that

$h=C_pT$

$h_1+\dfrac{V_1^2}{2}=h_2+\dfrac{V_2^2}{2000}$

$1.005\times 25+\dfrac{400^2}{2000}=1.005\times 100+\dfrac{V_2^2}{2}$

$V_2=96.43\ m/s$

So the exit velocity of air is 96.43 m/s.

8 0

4 years ago

6NaBr+1AlO3=3Na2O+2AlBr3 How many grams of NaBr would be needed in order to make 23.5 grams of AlBr3

Evgesh-ka [11]

Answer:

23.5 grams of AlBr3 will be produced by 27.20 grams of NaBr

Explanation:

The balanced equation here is

6NaBr + 1AlO3 = 3Na2O + 2AlBr3

6 moles of NaBr are required to produce 2 moles of AlBr3

Mass of one mole of NaBr = 102.894 g/mol

Mass of one mole of AlBr3 = 266.69 g/mol

Mass of 6 moles of NaBr = 6*102.894 g/mol

Mass of two moles of AlBr3 = 2*266.69 g/mol

6*102.894 g NaBr produces 2*266.69 g of AlBr3

23.5 grams of AlBr3 will be produced by (6*102.894)/(2*266.69 )*23.5 = 27.20 grams of NaBr

6 0

3 years ago

When you add water to calcium oxide it makes calcium hydroxide

Romashka [77]

Yes you add water to calcium oxide it makes calcium hydroxide

7 0

4 years ago

An sp3 hybridized nonpolar central atom can be used to describe the bonding in...

Andre45 [30]

The answer is A. An sp3 hybridized atom will have a total of 4 single bonds and lone pairs. Since carbon here is attached to four hydrogens, it must be sp3 hybridized. The C-H bonds are also the least polar bonds here, even though there is a slight amount of electronegativity difference between the two.

3 0

4 years ago