Answer:lanthanides is the answer and here is a picture for proof
Explanation:
77.60 ml of .210 M NaOH are required to neutralize 25.05 ml
1 answer:
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The percent of water in the hydrated salt will be 55.08 %
<h3>What is mass?</h3>Mass is a numerical measure of quantity, which is a basic feature of all matter. The kilogram is the international system of units of mass.
Given data;
Mass of crucible, cover, and contents before heating = 23.4 g.
Mass of empty crucible and cover = 18.82 g.
Mass of crucible, cover, and contents after heating to constant mass = 20.94 g.
⇒Mass of hydrated salt used = Mass of the crucible, cover, and contents before heating - Mass of the empty crucible and cover
⇒Mass of hydrated salt used = = 23.54 g – 18.82 g
⇒Mass of hydrated salt used = = 4.72 g
⇒Mass of dehydrated salt after heating = Mass of the crucible, cover, and contents after heating to constant mass-Mass of the empty crucible and cover
⇒Mass of dehydrated salt after heating = 20.94 g – 18.82 g
⇒Mass of dehydrated salt after heating = 2.12 g
⇒ Mass of water liberated from salt = Mass of hydrated salt used - Mass of dehydrated salt after heating
⇒ Mass of water liberated from salt = 4.72 g – 2.12 g
⇒ Mass of water liberated from salt = 2.60 g
Water % in the hydrated salt is found as;
% water =(mass of water/ mass of hydrated salt)× 100
% water =(2.60/4.72) × 100
% water =55.08 %
Hence the percent of water in the hydrated salt will be 55.08 %
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