Here is the full question
How many moles of sodium acetate must be added to 2.0 L of 0.10 M acetic acid to give a solution that has a pH equal to 5.00? Ignore the volume change due to the addition of sodium acetate. Ka of acetic acid is 1.7×10-5.
Answer:
0.3396 moles
Explanation:
pH = pKA + log
[acetic acid] = 0.1 M
pH = 5.0
=
5.0 = -log () + log
5.0 = 4.77 + log [acetate] + 1
5.0 = 5.77 + log [acetate]
- log [acetate] = 5.77 - 5.0
- log [acetate] = 0.77
log [acetate] = -0.77
[acetate] = log⁻¹ (-0.77)
[acetate] = 0.1698
∴ for 2L = 2 × 0.1698
= 0.3396 moles
The answer is by using chemical reactions.
Gram is the unit of weight and it comes under CGS measurement. CGS stands for centimeter for length, gram for mass and seconds for time whereas MKS system contains meter for length, kilogram for mas and seconds for time.
1 gram contains 1000 milligram such as:
For the conversion of gram to milligram,
Thus, 5000 mg is present in 5 g of compound