Question

If 63.5 mol of an ideal gas is at 9.11 atm at 42.80 °C, what is the volume of the gas?

Answer 1

The volume of the gas is 180.26 L, if there are 63.5 mol of an ideal gas at 9.11 atm at 42.80 °C.

Applying the ideal gas law PV= nRT

After rearranging the aforementioned expression, the volume might then be found as: V= n R T/ P.

Consequently, V= 63.5 mol, 0.0821, 315 K, and 9.11 atm equal 180.26 L.

How is the ideal gas equation defined?

The ideal gas equation is PV = nRT. In this equation, P denotes the ideal gas's pressure, V its volume, n its total amount, expressed in moles, and R its resistance for the universal gas constant, and T for temperature.

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