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Alekssandra [29.7K]
3 years ago
7

Could you guys help me find the area of these please? i don't understand how to do this

Mathematics
2 answers:
vova2212 [387]3 years ago
7 0

Answer:

for 9, the answer is 246.49

Step-by-step explanation:

This is area of a circle correct?

The formula is PI x radius squared.

3.14 x the radius, which is 5, squared

I am re-editing this

so sorry the answer is actually 78.54

The reason why it is 78.54 is that you need to square the radius before multiplying with PI.

Daniel [21]3 years ago
6 0

Step-by-step explanation:

okay, so the area of a circle can be found with the formula πr^2

this means you have to square the radius of the circle and multiply it by pi to find your answer.

9) r=5

πr^2

π(5)^2 = 25π or about 78.54cm^2

this is how you get the area of all other circles!

10) r=9

πr^2

π(9)^2 = 81π or about 254.47mi^2

11) r=8

πr^2

π(8)^2 = 64π or about 201.06mi^2

12) r=4.5

πr^2

π(4.5)^2 = 20.25π or about 63.62in^2

13) r=6.6

πr^2

π(6.6)^2 = 43.56π or about 136.85yd^2

14) r=2

πr^2

π(2)^2 = 4π or about 12.56cm^2

15) r=9

πr^2

π(9)^2 = 81π or about 254.47in^2

16) r=7

πr^2

π(7)^2 = 49π or about 153.94km^2

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Answer:

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given cot ( -270)

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so cot (-270) = - cot270

<u>trigonometry table</u>

          II quadrant                                I quadrant ( All positive)                                                                              

 sin θ            90+θ                                                    90 -θ

<u>  cosec</u> θ <u>     180-θ                                                   360+θ</u>

            third quadrant                                fourth quadrant

 tan θ            180+θ                                       cos θ          270+θ

 cot θ       270 - θ                                          sec θ       360-θ                                    

Given

cot (-270) = -cot ( 270)

                = - cot ( 180 + 90) (third quadrant above table)

                = -cot 90 =0 ( cot θ positive in third quadrant

<u>Final answer</u>:-

cot(-270) =0

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