What part of the coordinate plane is equidistant from the points A(-3,2) and B(3,2)? Explain.

2 answers:

5 0

1st find the midpoint
-3 + 3 = 0/2 = 0 for the x
2 + 2 = 4/2 = 4 for the y
the midpoint is (0,2) which is along the y-axis which is your answer

Tpy6a [65]4 years ago

4 0

Since the y-coordinates are the same, the part of the coordinate plane that is equidistant is going to be a vertical line.

Take the average of -3 and 3 to find the x value of the vertical line.
(-3+3)/2 = 0

The vertical line is going to be x=0.

That's pretty much the y axis!

Have an awesome day! :)

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