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Lilit [14]
3 years ago
11

a bicycle manufacturer needs 4 brake pads for each bicycle there 173 brake pads in stock how many bicycles can be made

Mathematics
1 answer:
olganol [36]3 years ago
6 0
Hey!
All you need to do is divide 173 by 4. that is 43.25. You can't have a fourth of a bicycle so you want to round down. You can make 43 bicycles. 
Hope this helps!
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Sergeu [11.5K]

Answer:

Step-by-step explanation:

From the picture attached,

Option A

From the given table,

Ratio of the 2nd value and 1st value = \frac{8}{4}=2

Ratio of 3rd value and 2nd value = \frac{16}{8}=2

There is a common ratio of 2.

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Option B

Given recursive formula of the sequence is,

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From this recursive formula sequence will be,

3, 15, 75, 375,.......

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Option C

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Option D

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Therefore, there is a common difference of 4 in each successive term to the previous term.

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max2010maxim [7]

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Step-by-step explanation:

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The sum of three consecutive even numbers is 114. what is the smallest of the three numbers?​
saul85 [17]

Answer:

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Step-by-step explanation:

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So, the consecutive even number will be (2n+2) followed by (2n+4).

We know that their sum must be 114. Therefore, we can write the following equation:

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6n+6=114

Subtract 6 from both sides:

6n=108

Finally, divide both sides by 6. Therefore, the value of n is:

n=108/6=18

Therefore, our first even number is 2n or 2(18) which equates to 36.

And the consecutive even numbers will be 38 and 40.

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4 0
3 years ago
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ladessa [460]

Step-by-step explanation:

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3 years ago
Consider two independent tosses of a fair coin. Let A be the event that the first toss results in heads, let B be the event that
aliina [53]

Answer with Step-by-step explanation:

We are given that two independent tosses of a fair coin.

Sample space={HH,HT,TH,TT}

We have to find that A, B and C are pairwise independent.

According to question

A={HH,HT}

B={HH,TH}

C={TT,HH}

A\cap B={HH}

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Using the formula

Then, we get

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P(B)=\frac{2}{4}=\frac{1}{2}

P(C)=\frac{2}{4}=\frac{1}{2}

If the two events A and B are independent then

P(A)\cdot P(B)=P(A\cap B)

P(A\cap)=\frac{1}{4}

P(B\cap C)=\frac{1}{4}

P(A\cap C)=\frac{1}{4}

P(A)\cdot P(B)=\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}

P(B)\cdot P(C)=\frac{1}{4}

P(A)\cdot P(C)=\frac{1}{4}

P(A)\cdot P(B)=P(A\cap B)

Therefore, A and B are independent

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Therefore, B and C are independent

P(A\cap C)=P(A)\cdot P(C)

Therefore, A and C are independent.

Hence, A, B and C are pairwise independent.

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