Slope of line = tan(120) = -tan(60) = - √3
Distance from origin = 8
Let equation be Ax+By+C=0
then -A/B=-√3, or
B=A/√3.
Equation becomes
Ax+(A/√3)y+C=0
Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/√3)y+C)/sqrt(A^2+(A/√3)^2))
Substitute coordinates of origin (x,y)=(0,0) =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/√(4/3) => C=8*2/√3 = (16/3)√3
Therefore one solution is
x+(1/√3)+(16/3)√3=0
or equivalently
√3 x + y + 16 = 0
Check:
slope = -1/√3 .....ok
distance from origin
= (√3 * 0 + 0 + 16)/(sqrt(√3)^2+1^2)
=16/2
=8 ok.
Similarly C=-16 will satisfy the given conditions.
Answer The required equations are
√3 x + y = ± 16
in standard form.
You can conveniently convert to point-slope form if you wish.
Answer:
The value of angle is 56.9°
Step-by-step explanation:
First, you have to find the length of hypotenuse using Pythagoras' Theorem, c² = a² + b² :
In order to find θ, you have to apply Sine Rule :
Answer:
847
Step-by-step explanation:
700 ÷100 = 7
7× 4.2 = 29.4
29.4×5 =147
500+147
Answer:
Ray DC and Ray DE
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
LCM OF 9, 15 = 45
LCM OF 2, 3, 5 = 30
LCM OF 12, 28 = 84
