Wallace took out a $5000 loan for 6 years. he is being charged 4% interest, compounded annually. calculate the total.
2 answers:
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Answer:
R80: 12
G150: 54
Best Profit: $582
Step-by-step explanation:
Let x and y represent the numbers of R80 and G150 players, respectively. The constraints of the problem are ...
0 ≤ x ≤ 18 . . . . . a maximum of 18 R80 can be built
0 ≤ y . . . . . . . . . only non-negative numbers can be built
9x +3y ≤ 270 . . . . ounces of plastic used cannot exceed 270
2x +6y ≤ 348 . . . . ounces of metal used cannot exceed 348
The objective is to maximize the profit function ...
P(x, y) = 8x +9y
The attached graph shows profit is a maximum of $582 per week when 12 R80 players and 54 G150 players are produced.
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Since the maximum profit is at a value of x less than 18, we didn't bother to graph that constraint.
