Question

Find 3 consecutive odd integers such that twice the sum of the first and third exceeds the second by fifteen

Answer 1

Answer:

The three consecutive odd integers are 3,5,7

How:

Let x, (x+2),(x+4) represent the three consecutive odd integers

Question states***  

2[x + (x+4)] = (x+2) + 15

 

solving for s

  4x + 8 = x + 17

    3x = 9

     x = 3   The three consecutive odd integers are 3,5,7