Question

Write an equation in standard form of the line passing through the points (3,3) and (-3,5)

Answer 1

Answer:

The equation of line AB  with points (3,3) and (-3,5) is given as

: x + 3y = 12

Step-by-step explanation:

Here, the given points are A (3, 3) and B (-3,5).

Now, slope of any line is given as :

$m = \frac{y_2 - y_1}{x_2 - x_1}$

or, $m = \frac{5-3}{-3 - 3} = \frac{2}{-6} = -\frac{1}{3}$

Hence, the slope of the line AB is (-1/3)

Now , A POINT SLOPE FORM of an equation is

(y - y0)  = m (x - x0) ; (x0, y0)  is any arbitrary point on line.

So, for the point (3,3) the equation of the line is

y - 3$y-3 = -\frac{1}{3} (x-3) \implies 3y - 9 = 3 -x$

Hence, the equation of line AB  with points (3,3) and (-3,5) is given as:

x + 3y = 12