Answer:
The first one is: The hydrogen bonds that form between water molecules account for some of the essential — and unique — properties of water. ... The attraction created by hydrogen bonds keeps water liquid over a wider range of temperature than is found for any other molecule its size.
The second one is: Before it overflows, the water forms a dome-like shape above the rim of the glass. This dome-like shape forms due to the water molecules’ cohesive properties, or their tendency to stick to one another. Cohesion refers to the attraction of molecules for other molecules of the same kind, and water molecules have strong cohesive forces thanks to their ability to form hydrogen bonds with one another.
The third one is: Water molecules want to cling to each other. At the surface, however, there are fewer water molecules to cling to since there is air above (thus, no water molecules). This results in a stronger bond between those molecules that actually do come in contact with one another, and a layer of strongly bonded water
This is the fourth: Water molecules are very good at forming hydrogen bonds, weak associations between the partially positive and partially negative ends of the molecules. Hydrogen bonding explains both the effectiveness of evaporative cooling (why sweating cools you off) and the low density of ice (why ice floats).
Explanation: i hope this helps it was a lot of typing!!!
Answer:
First two rings are thicker while the last two rings are thinner.
Explanation:
Due to the first two years of optimal growing conditions received by the tree, the width of trunk of the tree is thicker but due to drought conditions experienced by the tree during the most recent two years, there is very little increase occur in the width of the trunk because the tree is in stress condition and for that reason the ring of trunk is thinner as compared to first two years.
Answer:
1. metaphase I
2. telophase II
3. anaphase I
4.prophase II
5. prophase I
6. anaphase II
7. telophase I
8. metaphase II
Explanation:
1. During _metaphase I________, pairs of homologous chromosomes align in the center of the cell.2. During _telophase II___, the separated chromatids elongate and (usually) cytokinesis occurs, formingfour genetically distinct haploid daughter cells.3. During _anaphase I_______, homologous chromosomes separate by moving with the spindle microtubulestoward the poles.4. During __prophase II______, a spindle apparatus forms and individual chromosomes (each composed ofsister chromatids) begin to move toward the center of the cell.5. During _prophase I_______, chiasmata form and crossing-over occurs.6. During _anaphase II_______, sister chromatids separate and move toward the poles.7. During __telophase I______, the separated chromosomes cluster at the poles of the spindle and cytokinesis occurs, forming two daughter cells, each with a haploid set of replicated chromosomes.8. During ___metaphase II_____, individual chromosomes (each composed of sister chromatids) align in the center of the cell.
Wait what????? How many light years!?
1. The correct answer is: a. There are more mRNA bases than amino acids.
The transcription of monocistronic mRNA in prokaryotes is a rare process (it is more characteristic for the eukaryotes). Monocistronic mRNA is RNA, which encodes for only one or specific protein. Three bases of mRNA encode one amino acid of protein, thus it has more bases than amino acids of the final product, protein.
2. The correct statements are:
The mRNA contains 5' and 3' untranslated regions.
The stop codon does not code for an amino acid.
The start site of transcription is upstream of the start codon.
Each codon contains 3 RNA bases.
All of these approve that more bases are in mRNA since not all of them are translated into amin oacids.
Other statements are hallmarks of eukaryotic RNA processing, and therefore not relevant to prokaryotes.