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Reptile [31]
4 years ago
12

Phosphofructokinase is an allosteric enzyme that catalyzes the conversion of fructose 6-phosphate to fructose 1,6-bisphosphate,

an early step of glycolysis. in the presence of oxygen, an increase in the amount of atp in a cell would be expected to _____.
Biology
2 answers:
Pavlova-9 [17]4 years ago
8 0
<span>An increase in the amount of ATP in a cell would be expected to inhibit the enzyme and thus slow the rates of glycolysis and the citric acid cycle.</span>
Nuetrik [128]4 years ago
7 0
Phosphofructokinase is an allosteric enzyme that catalyzes the conversion of fructose 6-phosphate to fructose 1,6-bisphosphate. This a an early reaction in the glycolysis pathway that is a regulatory step in the pathway. An increase int he amount of ATP in the cell might cause decrease in the amount of phosphofructokinase enzyme by a process called feedback inhibition. Glycolysis process is regulated at various steps in which conversion of fructose 6-phosphate to fructose 1,6-bisphosphate is one of the regulatory step.

Answer: In the presence of oxygen, an increase in the amount of ATP in a cell would be expected to INHIBIT THE PHOSPHOFRUCTOKINASE ENZYME AND SLOWS THE RATE OF GLYCOLYSIS.
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Brums [2.3K]

Answer:

The first one is: The hydrogen bonds that form between water molecules account for some of the essential — and unique — properties of water. ... The attraction created by hydrogen bonds keeps water liquid over a wider range of temperature than is found for any other molecule its size.

The second one is: Before it overflows, the water forms a dome-like shape above the rim of the glass. This dome-like shape forms due to the water molecules’ cohesive properties, or their tendency to stick to one another. Cohesion refers to the attraction of molecules for other molecules of the same kind, and water molecules have strong cohesive forces thanks to their ability to form hydrogen bonds with one another.

The third one is: Water molecules want to cling to each other. At the surface, however, there are fewer water molecules to cling to since there is air above (thus, no water molecules). This results in a stronger bond between those molecules that actually do come in contact with one another, and a layer of strongly bonded water

This is the fourth: Water molecules are very good at forming hydrogen bonds, weak associations between the partially positive and partially negative ends of the molecules. Hydrogen bonding explains both the effectiveness of evaporative cooling (why sweating cools you off) and the low density of ice (why ice floats).

Explanation: i hope this helps it was a lot of typing!!!

5 0
4 years ago
A four-year-old tree with a woody trunk experienced optimal growing conditions during its first two years of growth and drought
Romashka-Z-Leto [24]

Answer:

First two rings are thicker while the last two rings are thinner.

Explanation:

Due to the first two years of optimal growing conditions received by the tree, the width of trunk of the tree is thicker but due to drought conditions experienced by the tree during the most recent two years, there is very little increase occur in the width of the trunk because the tree is in stress condition   and for that reason the ring of trunk is thinner as compared to first two years.

6 0
3 years ago
Match the words below to the appropriate blanks to complete the sentences.
galben [10]

Answer:

  1. metaphase I

2. telophase II

3. anaphase I

4.prophase II

5. prophase I

6. anaphase II

7. telophase I

8. metaphase II

Explanation:

1. During _metaphase I________, pairs of homologous chromosomes align in the center of the cell.2. During _telophase II___, the separated chromatids elongate and (usually) cytokinesis occurs, formingfour genetically distinct haploid daughter cells.3. During _anaphase I_______, homologous chromosomes separate by moving with the spindle microtubulestoward the poles.4. During __prophase II______, a spindle apparatus forms and individual chromosomes (each composed ofsister chromatids) begin to move toward the center of the cell.5. During _prophase I_______, chiasmata form and crossing-over occurs.6. During _anaphase II_______, sister chromatids separate and move toward the poles.7. During __telophase I______, the separated chromosomes cluster at the poles of the spindle and cytokinesis occurs, forming two daughter cells, each with a haploid set of replicated chromosomes.8. During ___metaphase II_____, individual chromosomes (each composed of sister chromatids) align in the center of the cell.

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Wait what????? How many light years!?
5 0
3 years ago
In prokaryotes, how does the length of a typical monocistronic mRNA compare to the length of the protein generated from this mRN
Nastasia [14]

1. The correct answer is: a. There are more mRNA bases than amino acids.

The transcription of monocistronic mRNA in prokaryotes is a rare process (it is more characteristic for the eukaryotes). Monocistronic mRNA is RNA, which encodes for only one or specific protein. Three bases of mRNA encode one amino acid of protein, thus it has more bases than amino acids of the final product, protein.  

2. The correct statements are:  

The mRNA contains 5' and 3' untranslated regions.

The stop codon does not code for an amino acid.

The start site of transcription is upstream of the start codon.

Each codon contains 3 RNA bases.

All of these approve that more bases are in mRNA since not all of them are translated into amin oacids.

Other statements are hallmarks of eukaryotic RNA processing, and therefore not relevant to prokaryotes.

5 0
3 years ago
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