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3 years ago

Help plz

Biology

2 answers:

AURORKA [14]3 years ago

8 0

Answer:

The answer is below

Explanation:

1. Path A (Atmosphere) :

Carbon Path: Atmospheric CO2: this arises from geological sources such as volcanoes, burning fossil fuels, etc. This gets carbon dioxide back into the atmosphere during these processes.

2. Path G (Geosphere)

Carbon Path: Lithosphere: Earth’s carbon has been researched to have large limestone deposits. This limestone can be found in the Earth's lithosphere. Through the heating of limestone, carbon dioxide gets back to the atmosphere.

3. Path H (Hydrosphere)

Carbon Path: Oceania CO2: there is a large deposit of dissolved CO2 underneath the ocean. As the ocean gets colder, it dissolves more. The plants absorbed carbon dioxide through photosynthesis and get back to the atmosphere

Gnoma [55]3 years ago

3 0

Answer:

Carbon Path: Atmospheric CO2: this arises from geological sources such as volcanoes, burning fossil fuels, etc. This gets carbon dioxide back into the atmosphere during these processes.

2. Path G (Geosphere)

3. Path H (Hydrosphere)

Explanation

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3 years ago

A genetic mutation causes a newt to have faster reflexes. After many generations, most of the newt population has the reflex mut

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Answer:

Explanation:

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22. A plant geneticist is investigating the inheritance of genes for bitter taste (Su) and explosive rind (e) in watermelon (Cit

mylen [45]

Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square ( $X^2$ ):

$X^2$ = $\frac{(O - E)^2}{E}$ where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The $X^2$ is calculated thus:

Phenotype O E $X^2$

1 88 164.81 $\frac{(88 - 164.81)^2}{164.81}$ = 35.80

2 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

3 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

4 81 18.31 $\frac{(81 - 18.31)^2}{18.31}$ = 214.64

Total $X^2$ = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

$X^2$ tabulated = 7.815

<em>The calculated </em> $X^2$ <em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently. </em>

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