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Inessa [10]
3 years ago
13

Solve each system by multiplying. Check ur answer.

Mathematics
1 answer:
kondor19780726 [428]3 years ago
7 0
Multiply all terms in the first equation by 2 and all terms in the second by 3.
You should obtain:

6x + 16y = 34
-6x + 27y = 9
------------------
       43y =43, and so y = 1.  Subbing 1 for y in the first eq'n, we get

3x + 8(1) = 17, or 3x = 9, or x = 3.

The solution is (3, 1).
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x^4 + 5x^3 - 12x^2 + 5x + 1

3 0
3 years ago
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Expressions and Equations
marissa [1.9K]

Answer:

a. Yes

b. Yes

c. Yes

d. No

Step-by-step explanation:

a. Because -10x+4x=6x

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( 2x + 1 ) + ( 3x+2 ) =
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Answer: 5x+3

Let's go over this problem step by step:

First, you need to combine all the line terms.

2x + 1 + 3x + 2

Next, you get this equation:

( 2x + 3x ) + ( 1 + 2 )

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7 0
3 years ago
Write (8a-^3) -2/3 in simplest form
Anna71 [15]

(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}

<em><u>Solution:</u></em>

<em><u>Given that,</u></em>

(8a^{-3})^{\frac{-2}{3}

We have to write in simplest form

<em><u>Use the following law of exponent</u></em>

(a^m)^n = a^{mn}

Using this, simplify the given expression

(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}

Thus the given expression is simplified

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3 years ago
S=4LW+2WH;S+=136,L6,W=4 WHAT IS H
Mekhanik [1.2K]

Answer:

H=5

Step-by-step explanation:

4 0
3 years ago
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