In algebra a term is a single number or letter so in this 5
x^2
-10xy
3y
y^2
-1
these are all the terms
B. Triangle B and Triangle D
Triangle A has all equal sides and Triangle C is a right triangle.
Y=6. you would replace x with 7 in the equation.
6(7) = 7y
42=7y
6=y
For elimination, multiply one whole equation by negative one (-1), then add or subtract according to your signs. After that, it will be a one-step equation.
3x + 4y = 19 3x + 4y = 19 3x + 4y = 19 -2y = -14 y = 7
3x + 6y = 33 -1 (3x + 6y = 33) -3x - 6y = -33 -14 / -2
Then you would go back and substitute the value of (y) back into either equation and then solve for the remaining variable (x). Finally, use both values to make an ordered pair.
3x + 4y = 19 3x = -9 x = -3 (-3 , 7)
3x + 4(7) = 19 (-9 / 3)
3x + 28 = 19
Good Luck
Answer:
Step-by-step explanation:
Given the expression ![\frac{\sqrt[5]{b} }{\sqrt[]{b} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B5%5D%7Bb%7D%20%7D%7B%5Csqrt%5B%5D%7Bb%7D%20%7D)
![\frac{\sqrt[5]{b} }{\sqrt[]{b} } \\= \frac{b^{1/5}}{b^{1/2}} \\= b^{1/5-1/2}\\= b ^{2-5/10}\\= b^{-3/10}\\Compare \ b^n \ with \ b^{-3/10}\\\\n = -3/10](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B5%5D%7Bb%7D%20%7D%7B%5Csqrt%5B%5D%7Bb%7D%20%7D%20%5C%5C%3D%20%5Cfrac%7Bb%5E%7B1%2F5%7D%7D%7Bb%5E%7B1%2F2%7D%7D%20%5C%5C%3D%20b%5E%7B1%2F5-1%2F2%7D%5C%5C%3D%20b%20%5E%7B2-5%2F10%7D%5C%5C%3D%20b%5E%7B-3%2F10%7D%5C%5CCompare%20%5C%20b%5En%20%5C%20with%20%5C%20%20b%5E%7B-3%2F10%7D%5C%5C%5C%5Cn%20%3D%20-3%2F10)
