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AlladinOne [14]
3 years ago
8

20 POINTS A landscape artist has drawn the outline of a house. Describe three different ways to make sure the corners of the hou

se are right angles. This was for Geometry. I was not given anything except for the above information.
Mathematics
1 answer:
Andru [333]3 years ago
3 0

Answer:

1. 3-4-5 method

2. Rope method

3. Optical square method

Step-by-step explanation:

1. A measuring tape, two ranging poles, pegs and three person's are needed.

First person holds together btw thumbs and finger the zero mark, the second person holds between thumb and finger the 3m mark on the tape and the third person holds the 8m, when all sides of the rope are stretched, a triangle is formed and angle near one is a right angle.

2. One loop of the rope is placed around peg A with a peg through other loop make a circle on the ground place peg B & C where circle crosses the base line and peg D is place half way between peg B & C, allowing peg D & A to form lines perpendicular to base line thereby forming a right angle.

3 this are simple instruments used to set out right angles and they are single and double prismatic square.

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1. A submarine is 40 meters below sea level. It goes up 12 meters, then goes down 30 meters. What is the submarine's new positio
Lilit [14]

Answer:

Question Number 1: C. -58 meters

Question Number 2: 1.45 lbs

Step-by-step explanation:

<em><u>Question Number 1: </u></em>

40 - 12 = 28 meters below sea level

28 + 30 = 58 meters below sea level . So respectively its negative, so -58 would be your answer .

<em><u>Question Number 2: </u></em>

To figure out how many pounds of carrots are in each cake, divided 7.25 by 5. That equals 1.45. So one cake needs 1.45 pounds of carrots.

8 0
3 years ago
Manuel drove 180 miles in 3 hours.What was his average rate?
nikdorinn [45]

Answer: 60 MPH

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
P(x) = x + 1x² – 34x + 343<br> d(x)= x + 9
Feliz [49]

Answer:

x=\frac{9}{d-1},\:P=\frac{-297d+378}{\left(d-1\right)^2}+343

Step-by-step explanation:

Let us start by isolating x for dx = x + 9.

dx - x = x + 9 - x > dx - x = 9.

Factor out the common term of x > x(d - 1) = 9.

Now divide both sides by d - 1 > \frac{x\left(d-1\right)}{d-1}=\frac{9}{d-1};\quad \:d\ne \:1. Go ahead and simplify.

x=\frac{9}{d-1};\quad \:d\ne \:1.

Now, \mathrm{For\:}P=x+1x^2-34x+343, \mathrm{Subsititute\:}x=\frac{9}{d-1}.

P=\frac{9}{d-1}+1\cdot \left(\frac{9}{d-1}\right)^2-34\cdot \frac{9}{d-1}+343.

Group the like terms... 1\cdot \left(\frac{9}{d-1}\right)^2+\frac{9}{d-1}-34\cdot \frac{9}{d-1}+343.

\mathrm{Add\:similar\:elements:}\:\frac{9}{d-1}-34\cdot \frac{9}{d-1}=-33\cdot \frac{9}{d-1} > 1\cdot \left(\frac{9}{d-1}\right)^2-33\cdot \frac{9}{d-1}+343.

Now for 1\cdot \left(\frac{9}{d-1}\right)^2 > \mathrm{Apply\:exponent\:rule}: \left(\frac{a}{b}\right)^c=\frac{a^c}{b^c} > \frac{9^2}{\left(d-1\right)^2} = 1\cdot \frac{9^2}{\left(d-1\right)^2}.

\mathrm{Multiply:}\:1\cdot \frac{9^2}{\left(d-1\right)^2}=\frac{9^2}{\left(d-1\right)^2}.

Now for 33\cdot \frac{9}{d-1} > \mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} > \frac{9\cdot \:33}{d-1} > \frac{297}{d-1}.

Thus we then get \frac{9^2}{\left(d-1\right)^2}-\frac{297}{d-1}+343.

Now we want to combine fractions. \frac{9^2}{\left(d-1\right)^2}-\frac{297}{d-1}.

\mathrm{Compute\:an\:expression\:comprised\:of\:factors\:that\:appear\:either\:in\:}\left(d-1\right)^2\mathrm{\:or\:}d-1 > This\: is \:the\:LCM > \left(d-1\right)^2

\mathrm{For}\:\frac{297}{d-1}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:d-1 > \frac{297}{d-1}=\frac{297\left(d-1\right)}{\left(d-1\right)\left(d-1\right)}=\frac{297\left(d-1\right)}{\left(d-1\right)^2}

\frac{9^2}{\left(d-1\right)^2}-\frac{297\left(d-1\right)}{\left(d-1\right)^2} > \mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}> \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

\frac{9^2-297\left(d-1\right)}{\left(d-1\right)^2} > 9^2=81 > \frac{81-297\left(d-1\right)}{\left(d-1\right)^2}.

Expand 81-297\left(d-1\right) > -297\left(d-1\right) > \mathrm{Apply\:the\:distributive\:law}: \:a\left(b-c\right)=ab-ac.

-297d-\left(-297\right)\cdot \:1 > \mathrm{Apply\:minus-plus\:rules} > -\left(-a\right)=a > -297d+297\cdot \:1.

\mathrm{Multiply\:the\:numbers:}\:297\cdot \:1=297 > -297d+297 > 81-297d+297 > \mathrm{Add\:the\:numbers:}\:81+297=378 > -297d+378 > \frac{-297d+378}{\left(d-1\right)^2}

Therefore P=\frac{-297d+378}{\left(d-1\right)^2}+343.

Hope this helps!

5 0
3 years ago
In a class of 30 students, 6 have a brother and 12 have a sister. There are 14 students
Elena-2011 [213]
30 students

14 have no siblings

that leaves 16 with siblings

6 have brothers and 12 have sisters which = 18 so 2 of the students have both a brother and a sister

2/30 students have a brother and a sister

1/15 chance
3 0
3 years ago
DOOOO NOTTT SKIPPPPPPP
Shalnov [3]
1st one RS=DE,
second one T=F,
last one R=D
7 0
3 years ago
Read 2 more answers
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