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4 years ago

If (a+b)^2 = 37 and ab=5 what is a^2 + b^2

Mathematics

2 answers:

vfiekz [6]4 years ago

6 0

(a+b)^2 = 37

a^2 + 2ab + b^2 = 37

Substitute ab = 5 into a^2 + 2ab + b^2 = 37

a^2 + 2(5) + b^2 = 37

a^2 + b^2 + 10 = 37

a^2 + b^2 = 27

Answer

a^2 + b^2 = 27

Setler79 [48]4 years ago

6 0

$(a+b)^2 = 37a^2 + 2ab + b^2 = 37\\a^2 + 2(5) + b^2 = 37\\a^2 + b^2 + 10 = 37\\a^2 + b^2 = 27$

Answer: 27

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