Var[2X + 3Y] = 2² Var[X] + 2 Cov[X, Y] + 3² Var[Y]
but since X and Y are given to be independent, the covariance term vanishes and you're left with
Var[2X + 3Y] = 4 Var[X] + 9 Var[Y]
X follows an exponential distribution with parameter <em>λ</em> = 1/6, so its mean is 1/<em>λ</em> = 6 and its variance is 1/<em>λ</em>² = 36.
Y is uniformly distributed over [<em>a</em>, <em>b</em>] = [4, 10], so its mean is (<em>a</em> + <em>b</em>)/2 = 7 and its variance is (<em>b</em> - <em>a</em>)²/12 = 3.
So you have
Var[2X + 3Y] = 4 × 36 + 9 × 3 = 171
Hi! i believe the answer is a, because if b (in this case 0.2) is less than 1 and greater than 0 its exponential decay!! good luck with the rest of your hw and i hope this helps
Answer:
b
Step-by-step explanation:
texas industries probably most affected most by agriculture
The coordinates of trapezoid vertices are:
- J(-7,-2);
- K(-4,-2);
- L(-2,-5);
- M(-9,-5).
The translation rule is
(x,y)→(x-2,y+8).
Then the image trapezoid vertices are:
- J'(-7-2,-2+8) that is J'(-9,6);
- K'(-4-2,-2+8) that is K'(-6,6);
- L'(-2-2,-5+8) that is L'(-4,3);
- M'(-9-2,-5+8) that is M'(-11,3)
Answer:
2 : 3
Step-by-step explanation:
We have 4 squares and 6 circles. We would like the ratio of squares to circles, so we divide 4 by 6:
4 / 6 ⇒ the ratio here would be 4 : 6
We need to simplify this. Notice that both 4 and 6 are divisible by 2. So, we can divide both by 2:
4/2 : 6/2 ⇒ 2 : 3
2 and 3 don't share any factors other than 1, so we leave the ratio like this.
The answer is thus 2 : 3.
<em>~ an aesthetics lover</em>