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Lelechka [254]
3 years ago
11

(10+-7 - -2) / (-2 - -1)

Mathematics
2 answers:
Scrat [10]3 years ago
4 0

Nice use of brackets. We know exactly what you mean.

(10 - 7 + 2) / (-2 + 1) Notice that with an even number of - signs, you get a plus and with and odd number you get a minus.

(5) / (-1) = - 5 answer

Edit

Numerator

10 does not change.

+ - 7 Here a plus and a minus are put together. There is 1 minus sign which is an odd number of minus signs so the 7 is minus

- - 2 Here there are 2 minus signs. They become plus because 2 is even, and an even number of minuses become a plus so you have +2

10 - 7 + 2 = 5

Denominator

-2 does not change. It remains minus 2.

- - 1 There are 2 minus signs so this becomes plus 1.

- 2 + 1 = - 1

Numerator over denominator = 5/-1 = - 5. I'll probably run out of editing time. If you still don't understand, try and pinpoint the problem and we'll keep trying until you do see it. This question is worth it.

SOVA2 [1]3 years ago
3 0
The answer is
(3 +2=5)/(-2 +1=-1)
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levacccp [35]

Answer:

90

Step-by-step explanation:

This is an increasing sequence, with -9 as its first term. The first increase is +3, then +5, +7, and +9. The differences increase by 2 each time. The sixth term will be 15 + 11, and the seventh would be 15 + 11 + 13. We can follow this pattern to get to the tenth term. 15 + 11 + 13 + 15 + 17 + 19 = 90

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3 years ago
Find the zero of each function and state the multiplicity of each zero. Please show all steps.
vodka [1.7K]

Answer:

1. y=(x+3)^3. Zero: x=-3 multiplicity 3.

2. y=(x-2)^2 (x-1). Zeros: x=2 multiplicity 2; x=1 multiplicity 1.

3. y=(2x+3)(x-1)^2. Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.


Step-by-step explanation:

1. y=(x+3)^3

y=0\\ (x+3)^3=0\\ \sqrt[3]{(x+3)^3}=\sqrt[3]{0}\\ x+3=0\\ x+3-3=0-3\\ x=-3

Zero: x=-3 multiplicity 3.


2. y=(x-2)^2 (x-1)

y=0\\ (x-2)^2(x-1)=0\\ \left \{ {{(x-2)^2=0} \atop {x-1=0}} \right\\ \left \{ {{\sqrt{(x-2)^2} =\sqrt{0} } \atop {x-1+1=0+1}} \right\\ \left \{ {{x-2=0} \atop {x=1}} \right\\ \left \{ {{x-2+2=0+2} \atop {x=1}} \right\\ \left \{ {{x=2} \atop {x=1}} \right.

Zeros: x=2 multiplicity 2; x=1 multiplicity 1


3. y=(2x+3)(x-1)^2

y=0\\ (2x+3)(x-1)^2=0\\ \left \{ {{2x+3=0} \atop {(x-1)^2=0}} \right\\ \left \{ {{2x+3-3=0-3} \atop {\sqrt{(x-1)^2} =\sqrt{0} }} \right\\ \left \{ {{2x=-3} \atop {x-1=0}} \right\\ \left \{ {{\frac{2x}{2} =\frac{-3}{2} } \atop {x-1+1=0+1}} \right\\ \left \{ {{x=-\frac{3}{2} } \atop {x=1}} \right.

Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.

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Answer:

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Step-by-step explanation:

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3 years ago
The distance between two cities is 87 km. What is the distance between them on a map drawn at a scale of 1:600,000?
Alexxx [7]

Answer:

<u>The correct answer is 14.5 centimeters on the map would be the distance between these two cities.</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Distance between two cities = 87 kilometers

Scale of the map = 1:600,000

2.  What is the distance between them on a map with that scale?

For finding out the answer to this question, we need to:

A. Convert 87 kilometers to centimeters, that is the average distance measurement of the maps, this way:

87 kilometers = 87,000 meters (multiplying by 10³)

87,000 meters = 8'700,000 centimeters (multiplying by 10²)

B. Now we divide the measurement in centimeters by the scale, this way:

8'700,000/600,000 = 14.5

<u>The correct answer is 14.5 centimeters on the map would be the distance between these two cities.</u>

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