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3 years ago

The answer is h=-1,9...help me pls

Mathematics

2 answers:

ahrayia [7]3 years ago

6 0

Answer:

h = -1, 9

Step-by-step explanation:

DochEvi [55]3 years ago

5 0

Answer:

see explanation

Step-by-step explanation:

Substitute x = - 4 into the equation and solve for h

3(- 4 + h)² = 75 ( divide both sides by 3 )

(- 4 + h)² = 25 ( take the square root of both sides )

-4 + h = ± $\sqrt{25}$ = ± 5

Add 4 to both sides

h = 4 ± 5

h = 4 - 5 = - 1 or h = 4 + 5 = 9

Hence h = - 1, 9

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Please help! Due tonight!

Kay [80]

Answer:

B. 6,8,10

Step-by-step explanation:

to find a right triangle the equation: a^2 + b^2 = c^2, so just plug each number in to see.

6^2 + 8^2 = !0^2

36 + 64 = 100

100 = 100

Personally i knew almost immediately because 3,4,5 are the most common right triangles example and 6,8,10 are just a x2 of them so yea.

3 0

3 years ago

Based on past experience, a telemarketing firm has found that calls to prospective customers take an average of 2.0 minutes, wit

xenn [34]

Answer: Our required probability would be 0.9641.

Step-by-step explanation:

Since we have given that

Number of hours he works a day = 8

So, Number of minutes he worked in a day = $8\times 60=480\ minutes$

Number of calls = 220

So, Average $=\bar{x}=\dfrac{480}{220}=2.18\ minutes$

Standard deviation $=s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1.5}{\sqrt{220}}=0.10$

Mean = μ = 2.0 minutes

Standard deviation = σ = 1.5 minutes

Using the normal distribution, we get that

$z=\dfrac{\bar{x}-\mu}{s}\\\\z=\dfrac{2.18-2.0}{0.10}\\\\z=1.8$

So, the probability that Albert will meet or exceed his quota would be

$P(X\leq 2.18)=P(z\leq 1.8)=0.9641$

Hence, our required probability would be 0.9641.

6 0

3 years ago

Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.) 3 217

Soloha48 [4]

Answer:

$f(216) \approx 6.0093$

Step-by-step explanation:

Given

$\sqrt[3]{217}$

Required

Solve

Linear approximated as:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

Take:

$x = 216; \triangle x= 1$

So:

$f(x) = \sqrt[3]{x}$

Substitute 216 for x

$f(x) = \sqrt[3]{216}$

$f(x) = 6$

So, we have:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

$f(215 + 1) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot f'(x)$

To calculate f'(x);

We have:

$f(x) = \sqrt[3]{x}$

Rewrite as:

$f(x) = x^\frac{1}{3}$

Differentiate

$f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}$

Split

$f'(x) = \frac{1}{3} \cdot \frac{x^\frac{1}{3}}{x}$

$f'(x) = \frac{x^\frac{1}{3}}{3x}$

Substitute 216 for x

$f'(216) = \frac{216^\frac{1}{3}}{3*216}$

$f'(216) = \frac{6}{648}$

$f'(216) = \frac{3}{324}$

So:

$f(216) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot \frac{3}{324}$

$f(216) \approx 6 + \frac{3}{324}$

$f(216) \approx 6 + 0.0093$

$f(216) \approx 6.0093$

6 0

3 years ago

PLEASE HELP!! GIVING BRAINIEST WHEN TWO PEOPLE ANSWER!!!

solniwko [45]

Answer:

Bright lemonade

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A student had 500 milliliters of water in a water bottle. She drank 25% of the water before soccer practice. After practice, she

marta [7]

A student had 500 milliliters of water in a water bottle. She drank 25% of the water before soccer practice. After practice, she drank 1/3 of the remaining water.

How much water, in milliliters, does the student have left in the bottle?

Answer:

the amount of water the student have left in the bottle is 250 milliliters

Step-by-step explanation:

A student had 500 milliliters of water in a water bottle. She drank 25% of the water before soccer practice. After practice, she drank 1/3 of the remaining water.

How much water, in milliliters, does the student have left in the bottle?

Before the soccer practice, she drank 25 % of the water

25% of the water = 25% of 500

= 25% × 500

= $\frac{25}{100}$ × 500

At the right hand-side of the equation, the two zeros will cancel-out the other two zeros, hence;

= 25 × 5

=125

25% of the water = 125 milliliters

From the question, it was said that drank 25% of the water before soccer, this implies that she drank 125 milliliters from the water bottles.

If she drank 125 milliliters of from a 500 milliliters water contain in the water bottle, then the amount of water left will be 500 ml - 125 ml = 375 ml

This implies that before the soccer practice she had 375 milliliters of water left in the water bottle.

After the practice, she drank 1/3 of the remaining water, which means after the practice she drank 1/3 of 375

1/3 of 375 = $\frac{1}{3}$ × 375 = $\frac{375}{3}$ = 125

After the practice she drank 125 milliliters of water from her 375 milliliters water.

The amount of water she have left after the practice will be;

375 milliliters - 125 milliliters = 250 milliliters

Therefore, the amount of water the student have left in the bottle is 250 milliliters

8 0

3 years ago