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3 years ago

the relative frequency of a drawing pin falling pin up is 3/8. How many times would you expect it to fall pin up in 400 drops?

1 answer:

4 0

Not really sure if this is correct since I'm really bad at math, but I think it'll be 150 times. Hope this helped child :)

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The area of the trapezoid is 40 square units.

Whitepunk [10]

Answer:

5 units

Step-by-step explanation:

Image of the trapezoid is attached.

To find the height of the trapezoid (image attached), let's take the formula for area of a trapezoid.

The formula for area of a trapezoid is:

$A = (\frac{a + b}{2}) h$

Here, a and b represents the bases of the trapezoid.

a = 6

b = 10

h which represents height is unknown.

A = 40

Substitute figures:

$40 = (\frac{6 + 10}{2}) h$

$40 = (\frac{16}{2}) h$

$40 = 8 * h$

Solve for h:

$h = \frac{40}{8}$

$h = 5$

The height of the trapezoid is 5 units

4 0

3 years ago

Read 2 more answers

A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square

kondaur [170]

This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

$V = xxy = x^{2}y$

We also know that the bin is constructed from 48 square feet of sheet metal, so:

Surface area of the square base = $x^{2}$

Surface area of the rectangular sides = $4xy$

Therefore, the total area of the cube is:

$A = 48 ft^{2} = x^{2} + 4xy$

Isolating the variable y in terms of x:

$y = \frac{48- x^{2} }{4x}$

Substituting this value in V:

$V = x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}$

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

$\frac{dv}{dx} = 48-3x^{2} =0$

Solving for x:

$x = \sqrt{\frac{48}{3}} = \sqrt{16} = 4$

Solving for y:

$y = \frac{48- 4^{2} }{(4)(4)} = 2$

Then, the dimensions of the largest volume of such a bin is:

Length = 4 ft
Width = 4 ft
Height = 2 ft

And its volume is:

$V = (4^{2} )(2) = 32 ft^{3}$

8 0

3 years ago

the length of a rectangular patio is 8 feet less than twice its width. the area of the patio is 280 square feet. find the dimens

jolli1 [7]

Answer:

The length of the rectangle 'l' = 20

The width of the rectangle 'w' = 14

Step-by-step explanation:

Explanation:-

Let 'x' be the width

Given data the length of a rectangular patio is 8 feet less than twice its width

2x-8 = length

The area of rectangle = length X width

Given area of rectangle = 280 square feet

x(2x-8) = 280

2(x)(x-4) =280

x(x-4) =140

x^2 -4x -140=0

x^2-14x+10x-140=0

x(x-14)+10(x-14)=0

(x+10)(x-14) =0

x = -10 and x = 14

we can choose only x =14

The width of the rectangle 14

The length of the rectangle 2x-8 = 2(14)-8 = 28 -8 =20

The length of the rectangle 'l' = 20

The width of the rectangle 'w' = 14

6 0

3 years ago

Do I multiply these fractions or how do I get the simplified answer

timama [110]

Answer:

Step-by-step explanation:

you have to add all the fractions to find the perimeter

10 1/7+10 1/7= 20 2/7 (width)

20 2/7+35 3/7(length) =55 5/7

12 2/7+12 2/7=24 4/7

55 5/7+24 4/7= 79 9/7=80 2/7

80 2/7+ 15 3/14+ 24 1/14= 562/7+ 213/14+337/14= (1124+213+337)/14

=1674/14=119 8/14= 119 4/7

6 0

2 years ago

Now write as multiplying 10 to a power by 10 to a power.

natita [175]

10^10 is 10000000000

7 0

2 years ago