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3 years ago

If you are a student with no assets of any value and have liability insurance on an old car that pays a

Mathematics

1 answer:

docker41 [41]3 years ago

4 0

Answer:

you pay 25, 000 from your own pocket and the insurance pays 50,000

Step-by-step explanation:

pls mark brainliest if this helped u

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8 ( 8x - 4) = -7 (-x - 5)

tiny-mole [99]

X=67/57 or X= 1.1754

6 0

3 years ago

5. Laney is 4 feet 8 inches tall. There are 2.54

Ede4ka [16]

The answer is C :) :)

6 0

3 years ago

Heyy!! Can someone help me please!!

abruzzese [7]

Answer:

7x + 14

Step-by-step explanation:

the first thing to do is expand the parentheses/brackets.

3(5x + 2) -2(4x - 4) will be

3(5x) + 3(2) -2(4x) -2(-4)

= 15x + 6 - 8x + 8

collect like terms

15x - 8x + 6 + 8 = 7x + 14

the answer is 7x + 14

5 0

3 years ago

Read 2 more answers

Yuto and Lian are at train stations 1,880 kilometers apart. Yuto boards a train heading east at an average speed of 220

Doss [256]

Answer:

1,000 km

Step-by-step explanation:

Assume that when two train pass each other, Lian has traveled x (km)

=> The time Lian has traveled when two trains pass each other is:

Time = Distance/ Rate = x/ 250 (hour)

As Lian and Yuto travelled from the two opposite train stations and the train stations are 1,880 km apart

=> When two train pass each other, Yuto has traveled 1,880 - x (km)

=> The time Yuto has traveled when two trains pass each other is:

Time = Distance/ Rate = (1,880 - x)/220 (hour)

As Lian and Yuto board at the same time, so that when two trains pass each other, the time both of them have traveled is equal

=> x/ 250 = (1,880 - x)/220

=> 220x = 250 x (1,880 -x)

=> 220x = 470,000 - 250x

=> 470x = 470,000

=> x = 1,000

So that, when two train pass each other, Lian has traveled x = 1,000 km

6 0

3 years ago

Read 2 more answers

Suppose that the value of a stock varies each day from $13 to $24 with a uniform distribution. (a) Find the probability that the

bogdanovich [222]

Answer:

a. P= 0.6364

b. P = 0.3636

c. Q = $21.25

d. P = 0.5

Step-by-step explanation:

given data

value of a stock varies = $13 to $24

solution

P (stock value is more than $17)

P = $\frac{(24-17)}{(24-13)}$

P = $\frac{7}{11}$

P = 0.6364

and

P (value of the stock is between $17 and $21)

P = $\frac{(21-17)}{(24-13)}$

P = $\frac{4}{11}$

P = 0.3636

and

Let the upper quartile be Q

$\frac{(24 - Q)}{(24 - 13)} = 0.25$

$\frac{(24 - Q)}{11} = 0.25$

(24 - Q) = 2.75

Q = $21.25

and

P(X > 20 | X > 16)

P = $\frac{(24-20)}{(24-16)}$

P = $\frac{4}{8}$

P = 0.5

3 0

4 years ago