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slega [8]
3 years ago
13

Compute the simplified numerical value of the expression: (4042 + 4040 + 4038 + … + 6 + 4 + 2) − (4041 + 4039 + 4037 + … + 5 + 3

+ 1).
Mathematics
1 answer:
Evgesh-ka [11]3 years ago
7 0

Answer:

2021

Step-by-step explanation:

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Tia’s tent is in the form of a triangular prism as shown below if Tia plans to waterproof the tent excluding the pace what is th
Marat540 [252]

just multiple it all together

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3 years ago
How many places do you need to move the decimal to the left to write the
Vlad [161]

Answer:

9

Step-by-step explanation:

the decimal always goes between the numbers that arent 0s

4 0
3 years ago
PQ¯¯¯¯¯ and PR¯¯¯¯¯ are tangent to ⊙ S. Identify PQ.<br> pls help 30 points
olga_2 [115]

Answer:

9

Step-by-step explanation:

Because line PQ and line PR are both tangent to circle S, it would result in them being equal. So first to find PQ, you would have to find the value of variable x. To do this you would set both equations equal to each other and solve

6x - 9 = 2x + 3

-2x       -2x

4x - 9 = 3

    +9   +9

4x = 12

x = 3

Now you have to substitute 3 back into the equation for PQ:

6(3) - 9

18 - 9

= 9

Resulting in PQ = 9, to check your answer, take the value of x (3) and substitute it into PR and you should also get 9

2(3) + 3

6 + 3

= 9

5 0
2 years ago
How do i rewrite y=8 (x - 5) (x +2) in standard form
Komok [63]

Answer:

Its already in standard form. LoL

Step-by-step explanation:

y=(x−5)(x+2)

6 0
3 years ago
My house is 20 miles from yours, but on the map it is only 4 mm away. What is the scale of the map? O A Imm = 5 mi B. I mm = 20
dlinn [17]

\huge \bf༆ Answer ༄

Let's use Unitary method to solve the question ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:4 \: mm \rightarrow20 \: miles

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:1 \: mm \rightarrow(20 \div 4) \: miles

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:1 \: mm \rightarrow5 \: miles

Therefore, 1 mm corresponds to 5 mile according to the map.

so, correct choice is ~

\overbrace{  \underbrace{\underline{ \boxed{ \sf A }}}}

7 0
2 years ago
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