All categories

3 years ago

Order the following numbers from least to greatest -9/2 0 1 3/5 9/7 2/3

Mathematics

2 answers:

marysya [2.9K]3 years ago

3 0

$\frac{-9}{2}$

$\frac{2}{3}$

$\frac{9}{7}$

1 $\frac{3}{5}$

stich3 [128]3 years ago

3 0

~Hello There!~

convert them all to decimals:

-4.5, 0, 1.6, 1.28571, 0.666666.

Now order them least to greatest:

-9/2, 0, 2/3, 1 3/5, 9/7

Hope This Helps You!

Good Luck :)

Have A Great Day ^_^

- Hannah ❤

You might be interested in

. Which of the following is the correct algebraic representation of the translation below?

stepladder [879]

Answer:

D) (x+6, y+5)

Step-by-step explanation:

You can start with the top corner of triangle A

Then count up 5 units and right 6 units

Because you count vertically 5 units that means you're using the y-axis, And because you're counting up, than means the values are positive.

And because you count horizontally 6 units you're using the x-axis, And you are counting to the right so the values are positive.

Down vertically=Negative Y-axis Values. Up vertically=Positive Y-axis Values

Right horizontally=Positive X-axis values. Left horizontally=Negative X-axis Values

8 0

3 years ago

Write the rule for finding the coordinates of a point’s 90⁰ clockwise rotation about the origin.

olga nikolaevna [1]

(x,y) -> (y,-x)

hope that help

4 0

3 years ago

A bag contains 4 blue marbles and 2 yellow marbles. Two marbles are randomly chosen (the first marble is NOT replaced before dra

VMariaS [17]

Answer:

0.4 = 40% probability that both marbles are blue.

0.0667 = 6.67% probability that both marbles are yellow.

53.33% probability of one blue and then one yellow

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

Step-by-step explanation:

To solve this question, we need to understand conditional probability(for the final question) and the hypergeometric distribution(for the first three, because the balls are chosen without being replaced).

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

What is the probability that both marbles are blue?

4 + 2 = 6 total marbles, which means that $N = 6$

4 blue, which means that $k = 4$

Sample of 2, which means that $n = 2$

This is P(X = 2). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,6,2,4) = \frac{C_{4,2}*C_{2,0}}{C_{6,2}} = 0.4$

0.4 = 40% probability that both marbles are blue

What is the probability that both marbles are yellow?

4 + 2 = 6 total marbles, which means that $N = 6$

2 yellow, which means that $k = 2$

Sample of 2, which means that $n = 2$

This is P(X = 2). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,6,2,2) = \frac{C_{2,2}*C_{4,0}}{C_{6,2}} = 0.0667$

0.0667 = 6.67% probability that both marbles are yellow.

What is the probability of one blue and then one yellow?

Total is 100%.

Can be:

Both blue(40%)

Both yellow(6.67%)

One blue and one yellow(x%). So

40 + 6.67 + x = 100

x = 100 - 46.67

x = 53.33

53.33% probability of one blue and then one yellow.

If you are told that both selected marbles are the same color, what is the probability that both are blue?

Conditional probability.

Event A: Both same color

Event B: Both blue

Probability of both being same color:

Both blue(40%)

Both yellow(6.67%)

This means that $P(A) = 0.4 + 0.0667 = 0.4667$

Probability of both being the same color and blue:

40% probability that both are blue, which means that $P(A \cap B) = 0.4$

Desired probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4}{0.4667} = 0.8571$

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

8 0

3 years ago

In a group of 60 students, 12 students take algebra one, 18 students take algebra 2 and 8 students take both subjects how many s

hoa [83]

60-12-18-2-8=20
=48-18-2-8
=30-2-8
=28-8
=20

So, 20 students don't take either of these subjects.

5 0

3 years ago

Which set of data represents a linear function?

AVprozaik [17]

The answer is d because the x value does not repeat. Hopes this helps.

5 0

3 years ago

Read 2 more answers