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weeeeeb [17]
3 years ago
15

Cluster sampling and stratified sampling both involve selecting subjects in subgroups of the population. what is the difference

between those two types of​ sampling?
Mathematics
2 answers:
Crank3 years ago
7 0

Cluster sampling and stratified sampling both involve selecting subjects in subgroups of the population. what is the difference between those two types of​ sampling?

Answer: Cluster sampling and stratified sampling both involve selecting subjects in subgroups of the population. But the difference is that in cluster sampling all the subjects of the selected subgroup are studied. While in stratified sampling, only randomly selected subjects of subgroups are studied.

Cluster Sampling is a probability sampling method where the target population is divided into clusters. Some of these clusters are selected randomly for sampling and all the members are studied under each randomly selected cluster.

Stratified Sampling is a probability sampling method, in which a population is divided into unique, homogeneous strata, members from these strata are randomly selected to form a sample.

balu736 [363]3 years ago
3 0

Answer:

In clustering sampling, the researcher test whole groups of people. In stratified, it's systematic choosing.

A census could be: which literary character is more popular in America: Harry potter or Sam Gamgee (Lord of the Rings)?  

First you would choose states to do the testing in, then cities. some of the clusters of people you choose will be tested as a whole (cluster testing). then, you would take random people from the other groups which were not tested as a whole to answer the question. (stratified sampling)

For both methods, divide a population into groups.

For cluster sampling, select all of the members in some of the groups.

For stratified sampling, select a random sample from each group.

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3 years ago
Use the linear combination method to solve this system of equations. What is the value of 3x+7y=3 X-7y=1
Allisa [31]

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3 years ago
What are the roots of the equation x^2+6x-9=10?
Ronch [10]

Answer:

-3+2sqrt7

-3-2sqrt7

Step-by-step explanation:

x^2+6x-9=10

x^2+6x-9-10=0

x^2+6x-19=0

ax^2+bx+c=0

a=1 b=6 c=-19

As cannot be solved by completing square we will use quadratic equation

x= (-b+sqrt(b^2-4ac))/2a     and      x= (-b-sqrt(b^2-4ac))/2a

x= (-6+sqrt(6^2-4*-19))/2     and      x= (-6-sqrt(6^2-4*-19))/2

x=(-6+sqrt(36+76))/2           and      x=(-6-sqrt(36+76))/2

x=(-6+4sqrt7)/2                   and       x=(-6-4sqrt7)/2

x=(-3+2sqrt7)                       and      x=(-3-2sqrt7)

x=2.29                                 and      x= -8.29

3 0
3 years ago
which is the correct simplified version of the expression shown after distrubuting and combining like terms? 1/3(9x-15)+2x​
zhannawk [14.2K]

Answer:11x + 5

Step-by-step explanation:1/3 times 9X is 3x. 1/3 times 15 is 5. Now you have 9x + 5 + 2x

9x + 2x = 11x

Final answer: 11x + 5

7 0
3 years ago
Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f
castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean (\mu) = 115 \times 20

= 2300

Standard deviation = 20 \times \sqrt{115}

Standard deviation (SD) = 214.4761

TO find:

a) P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})

P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})

P(x > 3500)= P(Z > \dfrac{1200}{214.4761})

P(x > 3500)= P(Z >5.595)

From the Z-table, since 5.595 is > 3.999

P(x > 3500)=1-0.9999

P(x > 3500) = 0.0001

b)

Here, the replacement time for the mean (\mu) = \dfrac{0+0.5}{2}

= 0.25

Replacement time for the Standard deviation \sigma = \dfrac{0.5-0}{\sqrt{12}}

\sigma = 0.1443

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = \sqrt{(115\times 20^2) +(114\times (0.1443)^2)}

= \sqrt{(115\times 400) +(114\times 0.02082249}

= \sqrt{(46000) +2.37376386}

= \sqrt{(46000) +(2.37376386)}

= \sqrt{46002.374}

= 214.482

Now; the required probability:

P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})

P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})

P(x > 4125) = P(Z >8.376)

P(x > 4125) =1-  P(Z

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0
2 years ago
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