I need to find the area of this

Jason gets paid $75 for 5 hours of lawn mowing. Jeremy mows lawns for 8 hours and is paid $160. What is the difference between t

prohojiy [21]

Answer:

the difference is 5 dollars between the two

Step-by-step explanation:

6 0

3 years ago

The author drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 200 times. Here are the observed

algol [13]

Answer:

$\chi^2 = \frac{(27-33.33)^2}{33.33}+\frac{(31-33.33)^2}{33.33}+\frac{(42-33.33)^2}{33.33}+\frac{(40-33.33)^2}{33.33}+\frac{(28-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33} =5.860$

$p_v = P(\chi^2_{5} >5.860)=0.32$

Since the p value is higher than the significance level assumed 0.05 we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we can assume that we have equally like results.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Number: 1, 2 , 3 , 4 , 5 ,6

Frequency: 27, 31, 42, 40, 28, 32

We need to conduct a chi square test in order to check the following hypothesis:

H0: The outcomes are equally likely.

H1: The outcomes are not equally likely.

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The observed values are given:

$O_{1}=27$ $O_{2}=31$

$O_{3}=42$ $O_{4}=40$

$O_{5}=28$ $O_{6}=32$

The expected values are given by:

$E_{1} =\frac{1}{6}*200=33.33$ $E_{2} =\frac{1}{6}*200=33.33$

$E_{3} =\frac{1}{6}*200=33.33$ $E_{4} =\frac{1}{6}*200=33.33$

$E_{5} =\frac{1}{6}*200=33.33$ $E_{6} =\frac{1}{6}*200=33.33$

And now we can calculate the statistic:

$\chi^2 = \frac{(27-33.33)^2}{33.33}+\frac{(31-33.33)^2}{33.33}+\frac{(42-33.33)^2}{33.33}+\frac{(40-33.33)^2}{33.33}+\frac{(28-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33} =5.860$

Now we can calculate the degrees of freedom for the statistic given by:

$df=Categories-1=6-1=5$

And we can calculate the p value given by:

$p_v = P(\chi^2_{5} >5.860)=0.32$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(5.860,5,TRUE)"

Since the p value is higher than the significance level assumed 0.05 we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we can assume that we have equally like results.

4 0

3 years ago

Anyone know how to do these and explain so I can do the rest lol.

klasskru [66]

Answer:

Option B. m⁷/n² is the correct answer.

Step-by-step explanation:

Identity,

xᵃ * xᵇ = xᵃ⁺ᵇ

xᵃ/xᵇ = xᵃ⁻ᵇ

x⁻ᵃ = 1/xᵃ

It is given that,

m⁻⁶ n⁻³/m⁻¹³ n⁻¹

Using these three identities we can write,

m⁻⁶ n⁻³/m⁻¹³ n⁻¹ = m⁻⁶ m¹³/n⁻¹n³ (since x⁻ᵃ = 1/xᵃ)

m⁻⁶ m¹³/n⁻¹n³ =m⁽⁻⁶⁺¹³⁾/n⁽⁻¹⁺³⁾ = m⁷/n² (since xᵃ * xᵇ = xᵃ⁺ᵇ and xᵃ/xᵇ = xᵃ⁻ᵇ)

Therefore Option B. m⁷/n² is the correct answer

6 0

3 years ago

Read 2 more answers

Two experiments are to be performed. The first can result in any one of m possible outcomes. If the first experiment results in

Galina-37 [17]

Answer: The first experiment has M probabilities, and the second has I(m) outcomes, that depends on the result of the first.

And lets call m to the result of the first experiment.

If the outcome of the first experiment is 1, then the second experiment has 1 possible outcome.

If the outcome of the first experiment is 2, then the second experiment has 2 possibles outcomes.

If the outcome of the first experiment is M, then the second experiment has M possibles outcomes.

And so on.

So the total number of combinations C is the sum of all the cases, where we exami

1 outcome for m = 1

+

2 outcomes for m=2

+

.

+

M outcomes for m = M

C = 1 + 2 + 3 + 4 +...´+M

7 0

3 years ago

there are 12 girls and 18 boys in a class. What is the largest number of groups they can be split up into and have the same numb

Veronika [31]

They all can be split up to 6 groups because 12+18=30 so each group will have 5 kids in it.

5 0

3 years ago