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2 years ago

Can u guys help me plz

Mathematics

2 answers:

Vaselesa [24]2 years ago

8 0

34.5 laps.
Tell me if you need to show your work

Varvara68 [4.7K]2 years ago

4 0

Your Answer Is 34.5 Laps
James Swam 34.5 or 35 and 1/2 laps

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Identify the parent function that can be used to graph the function f(x)= (1/4 x)^3

Kaylis [27]

Answer:

$f(x)=x^3$

Step-by-step explanation:

The parent function denotes the simplest function (free from any horizontal/vertical stretch/compression) that represents a family of functions. In this case the term 1/4 indicates a horizontal stretch and should be removed to find the parent function of $f(x)=x^3$ . From here we're in simplest form, since $y=x$ or others represent a completely different family of functions and cannot be obtained from horizontal/vertical stretches/compressions.

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3 years ago

The equation a2 + b2 = ca represents the relationship between the three sides of a right triangle.

choli [55]

Answer:

Step-by-step explanation:

I think you mean a² + b² = c², not ca.

a = 10, c = 26

b² = c² - a² = 26² - 10² = 576

b = √576 = 24 ft

3 0

3 years ago

If f(x) = 3x - 1 and g(x) = x + 2, find (f - g)(x).

Marat540 [252]

Answer:

(f - g)(x) = 2x - 3

Step-by-step explanation:

(f - g)(x) is defined as subtracting the whole g(x) function from the f(x) function.

Hence, we can define it as:

(3x - 1) - (x + 2)

= 3x - x - 1 - 2

= 2x - 3

Therefore, (f - g)(x) = 2x - 3.

Hope this helped!

6 0

2 years ago

Solve for x <br> 2x+16 X+16

nydimaria [60]

Answer:

2x(16)+16(16)

32x+256

32x/32=256/32

x=8

3 0

3 years ago

Read 2 more answers

I need help with #11

Troyanec [42]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template in mind, let's take a peek at this function

$\bf \begin{array}{lllcclll}
y=&2(&1x&-2)^2&-4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
A\cdot B=2\impliedby \textit{shrunk by a factor of 2, of half-size}\\\\
\cfrac{C}{B}= \cfrac{-2}{1}\implies -2\impliedby \textit{horizontal right shift of 2 units}\\\\
D=-4\impliedby \textit{vertical down shift of 4 units}$

so, the graph of y=2(x-2)²-4, is really the same graph of y=x², BUT, narrower, and moved about horizontally and vertically

8 0

3 years ago

Read 2 more answers